<span>4.9 L would be the answer to this question :)</span>
Answer:
You will have 19.9L of Cl2
Explanation:
We can solve this question using:
PV = nRT; V = nRT/P
<em>Where V is the volume of the gas</em>
<em>n the moles of Cl2</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is 273.15K assuming STP conditions</em>
<em>P is 1atm at STP</em>
The moles of 63g of Cl2 gas are -molar mass: 70.906g/mol:
63g * (1mol / 70.906g) = 0.8885 moles
Replacing:
V = 0.8885mol*0.082atmL/molK*273.15K/1atm
V = You will have 19.9L of Cl2
Where is the picture to this?
Answer:
mass = 508 g
Explanation:
Given data:
Number of moles of Cu = 8 mol
Mass in gram = ?
Solution:
Number of moles = mass/molar mass
Molar mass of Cu is 63.5 g/mol.
Now we will put the values in formula.
8 mol = mass /63.5 g/mol
mass = 63.5 g/mol
×8 mol
mass = 508 g
Answer: The rate constant is
Explanation ;
Expression for rate law for first order kinetics is given by:
where,
k = rate constant = ?
t = age of sample = 4.26 min
a = initial amount of the reactant = 2.56 mg
a - x = amount left after decay process = 2.50 mg
Now put all the given values in above equation to calculate the rate constant ,we get
Thus rate constant is [tex]0.334s^{-1}