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Ierofanga [76]
3 years ago
15

If a substance has a high hydronium concentration, the substance has a ____ pH.

Chemistry
1 answer:
aalyn [17]3 years ago
4 0

Answer: low pH

Hydronium is H^+ and acids give hydronium ions to water solution.

PH = -log H^+ concentration. The higher the concentration, the lower pH value

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Please;( urgent CuSO4•5H2O is blue
wariber [46]
Is that high school stuff or college?
6 0
3 years ago
How many particles are in 4g of NaCl? (1mol of NaCl = 58g) – 2 step conversion
oksian1 [2.3K]

Answer:

4.16 * 10²⁴ particles

Explanation:

1. We convert from grams to moles

4 g NaCl / 58 g of NaCl = 0.0689655172 moles

-> 0.0690 moles

2. Now we will convert from moles to particles by multiplying by avogadro's number..

0.0690 * 6.022 *10²³ = 4.15518 * 10²⁴ particles or 4.16 * 10²⁴ particles

4 0
3 years ago
A certain first-order reaction has a rate constant of 2.65×10−2s−1 at 16 ∘C. What is the value of k at 63 ∘C if Ea = 88.5 kJ/mol
alisha [4.7K]

Answer:

chemistry ka mujy b krna☹️

5 0
3 years ago
HELP
snow_lady [41]

Explanation:

a chemical reaction that absorbs energy is known to be endothermic since heat is being taken in by the reaction. The value of the transition state would be 150 because you have to subtract the product's enthalpy and the reactant's enthalpy to obtain it. A positive value for the transition state also corroborates that the reaction is endothermic.

5 0
3 years ago
An unknown compound containing only C and H was burnt, yielding 10.2 g of CO2 and 6.3 g of H2O. With a molecular weight of about
Lisa [10]

Answer:

C_2H_6

Explanation:

Hello.

In this case, we can see that the mass of carbon of the unknown compound comes from the yielded mass of carbon dioxide, thus, we compute the moles of carbon as follows:

m_C=10.2gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1mol C}{1molCO_2}=0.232 molC

Moreover, the mass of hydrogen comes from the yielded water, therefore we can also compute the moles of water:

m_H=6.3gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH_2}{1molH_2O}  =0.7molH

Then, to find the subscripts in the empirical formula, we divide by the moles of carbon as the smallest:

C:\frac{0.232}{0.232}=1\\ \\H:\frac{0.7}{0.232}=3

Whose molar mass is:

M_{CH_3}=12+1*3=15g/mol

Thus, the ratio of the molecular formula to the empirical formula is:

\frac{30}{15}=2

Therefore, the molecular formula is twice the empirical formula:

C_2H_6

Which is actually ethane.

Regards.

3 0
3 years ago
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