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Anton [14]
3 years ago
10

How many moles are there in 2 grams of Aluminum?

Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
3 0

Answer:

Number of moles: 0.07407407407

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ASAP PLS
AveGali [126]

Answer:

think I did this before and its V

8 0
3 years ago
If the actual yield of a reaction is 37.6 g while the theoretical yield is 112.8 g what is the percent yield
Zigmanuir [339]
<h2>Hello!</h2>

The answer is:

The percent yield of the reaction is 32.45%

<h2>Why?</h2>

To calculate the percent yield, we have to consider the theoretical yield and the actual yield. The theoretical yield as its name says is the yield expected, however, many times the difference between the theoretical yield and the actual yield is notorious.

We are given that:

ActualYield=37.6g\\TheoreticalYield=112.8g

Now, to calculate the percent yield, we need to divide the actual yield by the theoretical and multiply it by 100.

So, calculating we have:

PercentYield=\frac{ActualYield}{TheoreticalYield}*100\\\\PercentYield=\frac{37.6g}{112.8g}*100=0.3245*100=32.45(percent)

Hence, we have that the percent yield of the reaction is 32.45%.

Have a nice day!

8 0
3 years ago
Read 2 more answers
HELP ME WITH ONE OR BOTH OF THESE QUEATIONS PLEASEEEE
marta [7]

Answer:

2. 181.25 K.

3. 0.04 atm.

Explanation:

2. Determination of the temperature.

Number of mole (n) = 2.1 moles

Pressure (P) = 1.25 atm

Volume (V) = 25 L

Gas constant (R) = 0.0821 atm.L/Kmol

Temperature (T) =?

The temperature can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

1.25 × 25 = 2.1 × 0.0821 × T

31.25 = 0.17241 × T

Divide both side by 0.17241

T = 31.25 / 0.17241

T = 181.25 K

Thus, the temperature is 181.25 K.

3. Determination of the pressure.

Number of mole (n) = 10 moles

Volume (V) = 5000 L

Temperature (T) = –10 °C = –10 °C + 273 = 263 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

The pressure can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

P × 5000 = 10 × 0.0821 × 263

P × 5000 = 215.923

Divide both side by 5000

P = 215.923 / 5000

P = 0.04 atm

Thus, the pressure is 0.04 atm

6 0
3 years ago
Please help ill give you a 100 points! Its urgent!! Q^Q
Sergio [31]

Answer:

1. C.

Explanation:

8 0
2 years ago
Read 2 more answers
In the gas-phase reaction 2 A + B ⇌ 3 C + 2 D, it was found that, when 1.00 mol A, 2.00 mol B, and 1.00 mol D were mixed and all
Naddik [55]

Answer:

(i)The mole fractions are :

  • A=\frac{0.4}{4.3} \\=0.0930
  • B=\frac{1.4}{4.3} \\=0.3256
  • C=\frac{0.9}{4.3} \\=0.2093
  • D=\frac{1.6}{4.3} \\=0.3721

(ii)K=0.4508

(iii)ΔG = 1.974kJ

Explanation:

The given equation is :

2A+B⇄3C+2D

Let \alpha be the number of moles dissociated per mole of B

Thus ,

<em>The initial number of moles of :</em>

  • A=1
  • B=2
  • C=0
  • D=1

2A\\(1-2\alpha)     +  B\\2(1-\alpha)  ⇄  3C\\(3\alpha)   + 2D\\(1+2\alpha)

And finally the number of moles of C[tex] is 0.9Thus ,[tex]3\alpha=0.9\\\alpha=0.3[tex]The final number of moles of:[tex]A = 1-2\alpha=1-2*0.3=0.4mol[tex] [tex]B=2(1-\alpha)=2(1-0.3)=1.4mol[tex][tex]D=1+2\alpha=1+2*0.3=1.6mol[tex]Thus , total number of moles are : 0.4+1.4+0.9+1.6=4.3(i)The mole fractions are : [tex]A=\frac{0.4}{4.3} \\=0.0930

  • B=\frac{1.4}{4.3} \\=0.3256
  • C=\frac{0.9}{4.3} \\=0.2093
  • D=\frac{1.6}{4.3} \\=0.3721

(ii)

K=\frac{(P_C^3)(P_D^2)}{(P_A^2)(P_B)}

Where ,

P_A,P_B,P_C,P_D are the partial pressures of A,B,C,D respectively.

Total pressure = 1 bar .

∴

<em>P_A= 0.0930*1=0.0930</em>

<em>P_B= 0.3256*1=0.3256</em>

<em>P_C= 0.2093*1=0.2093</em>

<em>P_D= 0.3721*1=0.3721</em>

K=\frac{0.2093^3*0.3721^2}{0.0930^2*0.3256} \\K=0.4508

(iii)

ΔG=-RTlnK\\

ΔG = -8.314*(273+25)*ln(0.4508)\\=1973.96J\\=1.974kJ

3 0
2 years ago
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