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LenaWriter [7]
3 years ago
6

A) Show work, b) solve, and c) graph the solutions for −7+2x>−27

Mathematics
2 answers:
8_murik_8 [283]3 years ago
7 0

Answer:

x > -10

Step-by-step explanation:

−7+2x>−27

Add 7 to each side

−7+7+2x>−27+7

2x > -20

Divide each side by 2

2x/2 > -20/2

x > -10

Zanzabum3 years ago
6 0

Answer:

Solve:

-7 + 2x > -27

Add both sides by 7:

-7 + 7 +2 > -27 +7

2x > -20

-Divide both sides by 2:

\frac{2x}{2} > \frac{-20}{2}

x > -10

After you have the answer x > -10, circle the mark above -10 on the number and draw the arrow to the right.

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Complete question :

Cheddar Cheese

$3/lb

Swiss Cheese

$5/lb

Keisha is catering a luncheon. She has $30 to spend on a mixture of Cheddar cheese and Swiss cheese. How many pounds of cheese can Keisha get if she buys only Cheddar cheese? Only Swiss cheese? A mixture of both cheeses?

What linear equation in standard form can she use to model the situation?

Answer:

10 lbs of cheddar cheese

6 lbs of Swiss cheese

$3a + $5b = $30

Step-by-step explanation:

Given that :

Cheddar cheese = $3/lb

Swiss cheese = $5/lb

Total amount budgeted for cheese = $30

How many pounds of cheese can Keisha get if she buys only Cheddar cheese?

Pounds of cheedar cheese obtainable with $30

Total budget / cost per pound of cheddar cheese

$30 / 3 = 10 pounds of cheedar cheese

Only Swiss cheese?

Pounds of cheedar cheese obtainable with $30

Total budget / cost per pound of Swiss cheese

$30 / 5 = 6 pounds of Swiss cheese

A mixture of both cheeses?

What linear equation in standard form can she use to model the situation?

Let amount of cheddar cheese she can get = a

Let amount of Swiss cheese she can get = b

Hence,

(Cost per pound of cheddar cheese * number of pounds of cheddar) + (Cost per pound of Swiss cheese * number of pounds of Swiss cheese) = total budgeted amount

(3 * a) + (5 * b) = $30

$3a + $5b = $30

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