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3 years ago

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AT YOUR NEW JOB AT THE COFFEE SHOP, YOU SOLD 42 LARGE COFFEES AND 54 SMALL COFFEES WHAT WAS THE RATIO OF LARGE TO SMALL COFFEES

YOU SOLD? UNDER A MICROSCOPE. YOU COUNTED 48 AMOEBAS AND 56 PARAMECIUMS WHAT WAS THE AMOEBA TO PARAMECIUM RATIO?

1 answer:

Helen [10]3 years ago

7 0

Answer:

go Amoeba and Paramecium.

Step-by-step explanation:

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The side of a square measures (2x − 5) units. Part A: What is the expression that represents the area of the square? Show your w

kolbaska11 [484]

A. The area of a square is given as:

<span>A = s^2 </span>

Where s is a measure of a side of a square. s = (2 x – 5) therefore,

<span>A = (2 x – 5)^2 </span>

Expanding,

A = 4 x^2 – 20 x + 25

<span>B. The degree of a polynomial is the highest exponent of the variable x, in this case 2. Therefore the expression obtained in part A is of 2nd degree.</span>

Furthermore, polynomials are classified according to the number of terms in the expression. There are 3 terms in the expression therefore it is classified as a trinomial.

<span>C. The closure property demonstrates that during multiplication or division, the coefficients and power of the variables are affected while during multiplication or division, only the coefficients are affected while the power remain the same.</span>

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3 years ago

A local water company charges a flat fee of $5 per month, plus $0.0007 per gallons, and $0.0009 per gallon for every gallon for

cestrela7 [59]

Answer:

Total cost= $51

Step-by-step explanation:

<u>Giving the following information: </u>

Fixed cost= $5

From 0 to 40,000 gallons= $0.0007 per gallon

From 40,001 to infinity= $0.0009

<u>We need to calculate the total cost for 60,000 gallons:</u>

Total cost= 5 + 40,000*0.0007 + 20,000*0.0009

Total cost= $51

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3 years ago

The saucer for Aisha's teacup has a diameter of 6 inches. What is the saucer's radius?

Aleonysh [2.5K]

I think its 6 but im not sure to be exactly right

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2 years ago

What equation does the model represent

lara [203]

5 whole and 1/6 hope it help you

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2 years ago

Location is known to affect the number, of a particular item, sold by an auto parts facility. Two different locations, A and B,

Mama L [17]

We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

$\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$

In order to use t*, we need to check conditions for using a t-distribution first.

Random for both samples -- NOT STATED in the problem ∴ <u><em>proceed with caution</em></u>!
Independence for both samples: 130 < all items sold at Location A; 180 < all items sold at Location B -- we can reasonably assume this is true
Normality: CLT is not met; <u>n < 30</u> for both locations A and B ∴ <u><em>proceed with caution</em></u>!

<u>Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.</u>

<u>Solve for t*:</u>

<u></u>

We need the <u>tail area </u>first.

$\displaystyle \frac{1-.9}{2}= .05$

Next we need the <u>degree of freedom</u>.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

df for A: 13 - 1 = 12
df for B: 18 - 1 = 17
df for A - B: |12 - 17| = 5

Use a calculator or a t-table to find the corresponding <u>t-score for df = 5 and tail area = .05</u>.

t* = -2.015

Now we can use the formula at the very top to construct a confidence interval for two sample means.

$\overline {x}_A=39$
$s_A=8$
$n_A=13$
$\overline {x}_B = 55$
$s_B=2$
$n_B=18$
$t^{*}=-2.015$

Substitute the variables into the formula: $\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$ .

$39-55 \ \pm \ -2.015 \big{(}\sqrt{\frac{(8)^2}{13} +\frac{(2)^2}{18} } } \ \big{)}$

Simplify this expression.

$-16 \ \pm \ -2.015 (\sqrt{5.1453} \ )$
$-16 \ \pm \ 3.73139$

Adding and subtracting 3.73139 to and from -16 gives us a confidence interval of:

$(-20.5707,-11.4293)$

If we want to <u>interpret</u> the confidence interval of (-20.5707, -11.4293), we can say...

<u><em>We are 90% confident that the interval from -20.5707 to -11.4293 holds the true mean of items sold at locations A and B.</em></u>

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1 year ago