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Yanka [14]
3 years ago
12

AT YOUR NEW JOB AT THE COFFEE SHOP, YOU SOLD 42 LARGE COFFEES AND 54 SMALL COFFEES WHAT WAS THE RATIO OF LARGE TO SMALL COFFEES

YOU SOLD? UNDER A MICROSCOPE. YOU COUNTED 48 AMOEBAS AND 56 PARAMECIUMS WHAT WAS THE AMOEBA TO PARAMECIUM RATIO?
Mathematics
1 answer:
Helen [10]3 years ago
7 0

Answer:

go Amoeba and Paramecium.

Step-by-step explanation:

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What number is one-fourth of the way between 2 and 10.4
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10.4 - 2 = 8.4
1/4(8.4) = 2.1........2 + 2.1 = 4.1 <==
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WITH PICTURE!!3. What is the value of x in the regular polygon below? (3 points)
monitta

Answer: FIRST OPTION.

Step-by-step explanation:

Regular polygons are those polygons whose sides are equal in length and whose angles are all equal.

By definition each interior angle of a Regular polygon,is:

\frac{180 ( n -2 )}{n}  (In degrees)

Where "n" is the number of sides of the polygon.

Observe the Regular polygon given in the exercise.

Since it has 6 sides, you can conclude that it is an Hexagon. Then:

n=6

Substituting into  \frac{180 ( n -2 )}{n}  and evaluating, you get:

\frac{180 ( 6 -2 )}{6}=120\°

Knowing this, you can write the following equation:

3x=120

Finally, you must solve for "x" in order to find its value. This is:

x=\frac{120}{3}\\\\x=40

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4 years ago
Find the total surface area of a cylinder. Use 3.14 for pi
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Answer:

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2 years ago
An isosceles triangle’s altitude will bisect its base. Which expression could be used to find the area of the isosceles triangle
omeli [17]

Answer:

\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}

Step-by-step explanation:

The length of the base is the distance between the points 4+2i and 10+4i, so

\text{Base}=|10+4i-(4+2i)|=|10+4i-4-2i|=|6+2i|=\sqrt{6^2+2^2}=\\ \\=\sqrt{36+4}=\sqrt{40}

The middle point of the base is placed at point

\dfrac{4+2i+10+4i}{2}=\dfrac{6i+14}{2}=7+3i

The length of the height is the distance between the points 5+9i and 7+3i

\text{Height}=|5+9i-(7+3i)|=|5+9i-7-3i|=|-2+6i|=\sqrt{(-2)^2+6^2}=\\ \\=\sqrt{4+36}=\sqrt{40}

So, the area of the triangle is

A=\dfrac{1}{2}\cdot \text{Base}\cdot \text{Height}=\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}

4 0
3 years ago
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