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Pani-rosa [81]
3 years ago
11

How do i completely factor 9c^4-36c^2?

Mathematics
2 answers:
VLD [36.1K]3 years ago
8 0
You take out the biggest factor of 9 and 36 which is 9c^2. The factors both have the c variable in common so you take the least exponent and put it with the gcf.

9c^2(c^2+4)
velikii [3]3 years ago
3 0
You would do
(3c^2+6c)(3c^2-6c)
since 3c^2 squared becomes 9c^4
and 6c times negative 6c becomes -36c^2

I just checked over and it would become
3c^2+6c[3c(c-2)]
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diamong [38]

Answer:

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Step-by-step explanation:

Evaluate for x=

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8 /9  + 8 /27

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(Decimal: 1.185185)

6 0
3 years ago
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jeka94

Assignment: \bold{Solve \ \left(-2x^2\right)^3\cdot \:3x}

<><><><><>

Answer: \boxed{\bold{-24x^7}}

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Explanation: \downarrow\downarrow\downarrow

<><><><><>

[ Step One ] Rewrite \bold{\left(-2x^2\right)^3}

\bold{-2^3\left(x^2\right)^3}

[ Step Two ] Rewrite Equation

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4 0
3 years ago
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kobusy [5.1K]

Answer: C=270x+2200

Step-by-step explanation:

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Cost per student in the year 1978 is $2200

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3 years ago
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4 years ago
How many solutions are there in the given equation?<br> y = 2x² + 6x + 4
tigry1 [53]

Step-by-step explanation:

Use the quadratic formula

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

2

+

6

+

4

=

0

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2

a={\color{#c92786}{2}}

a=2

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6

b={\color{#e8710a}{6}}

b=6

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c={\color{#129eaf}{4}}

c=4

=

−

6

±

6

2

−

4

⋅

2

⋅

4

√

2

⋅

2

x=\frac{-{\color{#e8710a}{6}} \pm \sqrt{{\color{#e8710a}{6}}^{2}-4 \cdot {\color{#c92786}{2}} \cdot {\color{#129eaf}{4}}}}{2 \cdot {\color{#c92786}{2}}}

x=2⋅2−6±62−4⋅2⋅4

brainliest and follow and thanks

8 0
3 years ago
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