$21 I believe (it's 1 am where I am so I'm not 100% sure but I think it's correct)
Well this problem can be solved with Algebra
the rule here is that for every incrementing sequence you increase your number by 6.
T(n)=18+6(n-1)
for 603 to be in the sequence, it has to male sense with the function above
603=18+6(n-1)
603-18=585
585=6(n-1)
n-1=(585/6)
n=(585+6)/6
n=591/6
here is your answer.
Fx - fa÷x - ( aif x ÷ n (2.178282)) (a) = -2.718282a² fix²+ fnx² - afn ÷ nx
Answer:
- -6x² - 6 = -7x - 9
- -6x² + 7x - 6 + 9 = 0
- -6x² + 7x + 3 = 0
- 6x² - 7x - 3 = 0
<u>Discriminant:</u>
- D = (-7)² - 4*6*(-3) = 49 + 72 = 121
<u>Since D > 0, there are 2 real solutions:</u>
- x = (- (-7) ±√121 )/12
- x = (7 ± 11)/12
- x = 1.5, x = -1/3
Answer:
110 grams
Step-by-step explanation:
CO2 molecule is made up of Carbon (atomic mass =12) and oxygen (atomic mass=16).
So first finding the mass of 1 molecule of CO2 which is equals to
= mass of 1 carbon atom + masses of 2 oxygen atom, we get
= 12+(16*2)= 12+32= 44 a.m.u.
Now 1 molecule of CO2 has mass 44 amu so mass of 1 mole CO2 will be 44 grams.( 1 a.m.u.=1.6729*10^-33 grams. 1 mole = 6.022*10^23, so 44 a.m.u.=73.6076*10^-33 grams approx. For one mole CO2, 73.6076*10^-33*6.022*10^23 which is approximately equals to 44 grams. )
1 mole CO2= 44grams, so 2.5 moles = 44*2.5= 110 grams
So our answer is 110 grams.
lowkey hope this helped you, good luck whatever you need it for Imaooo
