At this point in time, you can use a technique called cross-mutiplication, where you say that
, and
at this point in time, you can devide each side by 8 and solve
Answer:
if Q={1,3,5,7,9}Express it in description methods
Answer:
y=-x+
Step-by-step explanation:
Answer:
x = -2 or x = 1/3 thus: B & C
Step-by-step explanation:
Solve for x over the real numbers:
2 x^2 + 7 x - 2 = 2 x - x^2
Subtract 2 x - x^2 from both sides:
3 x^2 + 5 x - 2 = 0
The left hand side factors into a product with two terms:
(x + 2) (3 x - 1) = 0
Split into two equations:
x + 2 = 0 or 3 x - 1 = 0
Subtract 2 from both sides:
x = -2 or 3 x - 1 = 0
Add 1 to both sides:
x = -2 or 3 x = 1
Divide both sides by 3:
Answer: x = -2 or x = 1/3
Answer:
2.28% probability that a person selected at random will have an IQ of 110 or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a person selected at random will have an IQ of 110 or higher?
This is 1 subtracted by the pvalue of Z when X = 110. So
has a pvalue of 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or higher