4. How will you find the volume of an irregularly shaped object that would dissolvein water?

2 answers:

5 0

Put a container in the water and the water displaced is the volume of the container and record it
Refill the eureka can and put in both the container while it contains the dissolvable substance and record the volume of the water displaced
Subtract the second volume of water displaced from the first volume of water displaced to get volume of the dissolvable substance

Dimas [21]3 years ago

4 0

Um you should putting it in a object that it can fill then go from there

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A 1,70 atm, una muestra de gas ocupa 4,25 litros. Si la presión en el gas aumenta a 2.40 atm, ¿cuál será el nuevo volumen?

statuscvo [17]

At 1.70 atm, a gas sample occupies 4.25 liters. If the pressure in the gas increases to 2.40 atm, what will the new volume be?

Answer:

3.01L

Explanation:

Given parameters:

Initial pressure, P1 = 1.7atm

Initial volume, V1 = 4.25L

Final pressure, P2 = 2.4atm

Unknown:

Final or new volume, V2 = ?

Solution:

To solve this problem, we use Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes, if the temperature is constant".

P1 V1 = P2 V2

P1 is the initial pressure

V1 is the initial volume

P2 final pressure

V2 final volume

1.7 x 4.25 = 2.4 x V2

V2 = 3.01L

8 0

3 years ago

A small sphere has a harge of 9uC and other small sphere has a charge of 4uC.

Helga [31]

Answer:

Electrical force, F = 90 N

Explanation:

It is given that,

Charge on sphere 1, $q_1=9\ \mu C=9\times 10^{-6}\ C$

Charge on sphere 2, $q_1=4\ \mu C=4\times 10^{-6}\ C$

Distance between two spheres, d = 6 cm = 0.06 m

Let F is the electrical force between them. It is given by the formula of electric force which is directly proportional to the product of charges and inversely proportional to the square of distance between them such that,

$F=k\dfrac{q_1q_2}{d^2}$