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yarga [219]
2 years ago
11

a car starts from the rest and accelerates at 9.54m/s for 6.5 seconds. what is the distance covered by the car​

Physics
1 answer:
uysha [10]2 years ago
3 0

Answer:

= 201.53 meters

Explanation:

A car started from rest and accelerated at 9.54 m/s^2 for 6.5 seconds. How much distance was covered by the car?

Use the formula  d = \frac{at^{2} }{2} ,

where d is the distance, t is the time and "a" is the acceleration.
d=\frac{9*54*6*5^{2} }{2} = 201.53 m

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Two point charges are 10.0cm apart and have charges of 2.0uC and -2.0uC, respectively. What is the magnitude of the electric fie
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The electric field generated by a point charge is given by:
E= k_e \frac{Q}{r^2}
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while the electric field generated by the negative charge is:
E_2=k_e \frac{Q_1}{r^2}=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(-2.0 \cdot 10^{-6} C)}{(0.05 m)^2} =-7.19 \cdot 10^6 N/C
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If we assume that the positive charge is on the left and the negative charge is on the right, we see that E1 is directed to the right, and E2 is directed to the right as well. This means that the net electric field at the midpoint between the two charges is just the sum of the two fields:
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The force on charge Y is the same as the force on charge X

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In this problem, we can identify object A as charge X and object B as charge Y. The magnitude of the electrostatic force between them is given by

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I think that the best one is determining one's sense of individuality and place in society.

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Convert the mass to kgs thanks
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Memorize this and you'll be able to do ALL of these:  <em>1  kg = 1,000 g</em>

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