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yarga [219]
2 years ago
11

a car starts from the rest and accelerates at 9.54m/s for 6.5 seconds. what is the distance covered by the car​

Physics
1 answer:
uysha [10]2 years ago
3 0

Answer:

= 201.53 meters

Explanation:

A car started from rest and accelerated at 9.54 m/s^2 for 6.5 seconds. How much distance was covered by the car?

Use the formula  d = \frac{at^{2} }{2} ,

where d is the distance, t is the time and "a" is the acceleration.
d=\frac{9*54*6*5^{2} }{2} = 201.53 m

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The magnitude of the frictional force along the plane is most nearly​
Svetach [21]

Answer:

F = N*μ or F =m*g*μ

Explanation:

The friction force is defined as the product of the normal force by the corresponding friction factor.

When a body is in equilibrium over a horizontal plane its normal force value shall be equal to:

N = m*g\\where:\\m=mass [kg]\\g=gravity [m/s^2]\\N= normal force [N]

if we simplify this formula more for a balanced body on a horizontal plane, we will have.

F=m*g*u

3 0
3 years ago
Which of the following BEST explains how good body composition is attained?
Ahat [919]
Supposing these are the choices, 

a. taking in a greater amount of energy than is released by the body
b. taking in a lesser amount of energy than is released by the body
c. balancing the amount of energy that is taken in with the amount of energy that is released by the body
<span> d. none of the above 

If we assume they are talking about a person who is with in an ideal body weight range than
c. is the correct answer.

Answer A will make you gain weight, B will make lose weight.
To fully complete the answer we would have to assume that the person has moderate exercise in their life style to maintain muscle mass.</span><u />
5 0
3 years ago
find the rate of energy radiated by a man by assuming the surface area of his body 1.7m²and emissivity of his body 0.4​
Dima020 [189]

The rate of energy radiated by the man is 3.86 x 10^{-8}  J/s. m^{2}.

The amount of energy radiated by an object majorly depends on the area of its surface and its temperature. The is well explained in the Stefan-Boltzmann's law which states that:

Q(t) = AeσT^{4}

where: Q is the quantity of heat radiated, A is the surface area of the object, e is the emmisivity of the object, σ is the Stefan-Boltzmann constant and T is the temperature of the object.

To determine the rate of energy radiated by the man in the given question;

\frac{Q(t)}{T^{4} } = Aeσ

But A = 1.7 m², e = 0.4 and σ = 5.67 x 10^{-8} J/s.

So that;

\frac{Q(t)}{T^{4} } = 1.7 * 0.4 * 5.67 x 10^{-8}

     = 3.8556 x 10^{-8}

     = 3.86 x 10^{-8}  J/s. m^{2}

Thus, the rate of energy radiated by the man is 3.86 x 10^{-8}  J/s. m^{2}.

Learn more on energy radiation of objects by visiting: brainly.com/question/12550129

4 0
3 years ago
Long-term mineral extraction has no lasting consequences.
Komok [63]

Answer:

False

Explanation:

5 0
3 years ago
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Genrish500 [490]

I think so, from his hair, he looks homophobic

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3 years ago
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