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yarga [219]
2 years ago
11

a car starts from the rest and accelerates at 9.54m/s for 6.5 seconds. what is the distance covered by the car​

Physics
1 answer:
uysha [10]2 years ago
3 0

Answer:

= 201.53 meters

Explanation:

A car started from rest and accelerated at 9.54 m/s^2 for 6.5 seconds. How much distance was covered by the car?

Use the formula  d = \frac{at^{2} }{2} ,

where d is the distance, t is the time and "a" is the acceleration.
d=\frac{9*54*6*5^{2} }{2} = 201.53 m

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Spaceship 1 and Spaceship 2 have equal masses of 300 kg. Spaceship 1 has an initial momentum magnitude of 600 kg-m/s. What is it
kati45 [8]

Answer:

Initial speed of the spaceship 1, v = 2 m/s

Explanation:

Given that :

Mass of spaceship 1 and 2 that have equal mass are 300 kg

Initial momentum of the spaceship 1 is 600 kg-m/s

To find :

We need to find the initial momentum of spaceship 1.

Solve :

The momentum of an object is equal to the product of mass and its velocity. Its SI unit is kg-m/s. Mathematically, it is given by :

p=mv

v=\dfrac{p}{m}

v=\dfrac{600\ kg-m/s}{300\ kg}

v = 2 m/s

Therefore the initial speed of spaceship 1 is 2 m/s. Hence, this is the required solution.

6 0
4 years ago
A pipe originally has a radius of 1.25m. It narrows down to a radius of 0.55m. If the original force in the big pipe is 72N, wha
Gemiola [76]

Use direct proportionality: If 1.25 m = 72 N, then 0.55 m = y

0.55 m × 72 = 39.6.

39.6÷1,25 gives you your answer which is 31.68 N.

5 0
3 years ago
A pile driver lifts a 450 kg weight and then lets it fall onto the end of a steel pipe that needs to be driven into the ground.
nikitadnepr [17]
The gravitational potential energy becomes work driving the pipe 

<span>m g h = f d </span>

<span>450 * g * 1.5 = f * .45</span>
6 0
3 years ago
Read 2 more answers
A physics student notices that 4.0 waves arrive at a beach every 20 seconds. The frequency of the wave is
Nadusha1986 [10]
1 wave per 5 seconds
4 0
3 years ago
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a carnot engine absorbs 200J of heat from a reservoir at the temperature of the normal boiling point of water and rejects heat t
emmainna [20.7K]

Answer:

The heat rejected is 146J.

The work done by the engine is 54J.

The thermal efficiency is 0.27

Explanation:

The efficiency of the carnot engine, which is working between a hot source at a temperature T_{1} and a cold source at a temperature T_{2}, is given by:

Efficiency=1-\frac{T_{2}}{T_{1}}

The normal boiling point of water is 373 K. (T_{1})

The temperature of triple point of water is 273.15 K (T_{2})

Efficiency=1-\frac{273.15}{373}=0.27

Efficiency=\frac{Work\:done}{Heat\:absorbed}=\frac{Work\:done}{200}=0.27\\Work\:done=0.27\times200=54J\\Work\:done=Heat\:absorbed-Heat\:rejected\\Heat\:rejected=Heat\:absorbed-Work\:done=200-54=146J

6 0
4 years ago
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