Answer:
It will be A. So since its 2 times more the kinetic energy. But then you have to square it 2^2 = 4
In #8, the distance and the (magnitude of displacement) are equal, because he crawled in a straight line.
Displacement = (straight-line distance from start-point to end-point) in the direction from start to end, regardless of what route was actually followed.
Displacement = 5m, in the negative direction.
In #9 . . . distance will be the same. Displacement is going to be the same magnitude, but in the positive direction.
This is so simple that it's hard to talk about.
In #8, "What was the bug's distance ?". "Distance was 5 meters.". "What was the bug's displacement ?", "Displacement was 5 meters backwards."
In #9, What was the bug's distance ?". "Distance was 5 meters.". "What was the bug's displacement ?", "Displacement was 5 meters forward."
Answer:
a)
14 rad/s
b)
11.2 m/s
Explanation:
a)
d = diameter of tire = 0.80 m
r = radius of tire = (0.5) d = (0.5) (0.80) = 0.40 m
v = speed of bicycle = 5.6 m/s
w = angular speed of the tire
Speed of cycle is given as
v = r w
5.6 = (0.40) w
w = 14 rad/s
b)
v' = speed of blue dot
Speed blue of dot is given as
v' = v + rw
v' = 5.6 + (0.40) (14)
v' = 11.2 m/s
