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kari74 [83]
3 years ago
15

A line is parallel to y = 5x + 9 and

Mathematics
1 answer:
ch4aika [34]3 years ago
5 0

Answer:

y = 5x + 7

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 5x + 9 ← is in slope- intercept form

with slope m = 5

Parallel lines have equal slopes, thus

y = 5x + c ← is the partial equation

To find c substitute (- 2, - 3) into the partial equation

- 3 = - 10 + c ⇒ c = - 3 + 10 = 7

y = 5x + 7 ← equation of parallel line

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An airport limousine can accommodate up to four passengers on any one trip. The company will accept a maximum of six reservation
Andrej [43]

Answer:

0.23328,2.4

Step-by-step explanation:

Given that an airport limousine can accommodate up to four passengers on any one trip. The company will accept a maximum of six reservations for a trip, and a passenger must have a reservation.

Assuming independence we can say persons who do not show up is binomial with p = 0.4 and n = 6

a) If six reservations are made, what is the probability that at least one individual with a reservation cannot be accommodated on the trip

= P(X\leq 1)\\=0.23328

b) Expected no of available places = E(x)=np = 6(0.4) = 2.4

8 0
3 years ago
What are the remaining trig functions? and how do i solve for them? pls help
erastovalidia [21]

You're told that tan(<em>θ</em>) is positive, but

tan(<em>θ</em>) = sin(<em>θ</em>)/cos(<em>θ</em>)

and you're also told that sec(<em>θ</em>) = 1/cos(<em>θ</em>) = -3. So if cos(<em>θ</em>) is negative, sin(<em>θ</em>) must also be negative. In turn, both sec(<em>θ</em>) = 1/cos(<em>θ</em>) and csc(<em>θ</em>) = 1/sin(<em>θ</em>) are also negative.

Now, recall the Pythagorean identity,

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1

Multiply through both sides by 1/cos²(<em>θ</em>) to get an alternate form of the identity,

1 + tan²(<em>θ</em>) = sec²(<em>θ</em>)

Solve for tan(<em>θ</em>) (which we know is positive):

tan(<em>θ</em>) = √(sec²(<em>θ</em>) - 1) = 2√2

Right away, we get

cot(<em>θ</em>) = 1/tan²(<em>θ</em>) = 1/(2√2) = √2/4

Since sec(<em>θ</em>) = -3, it follows that cos(<em>θ</em>) = -1/3.

Then

tan(<em>θ</em>) = sin(<em>θ</em>)/cos(<em>θ</em>)   ==>   sin(<em>θ</em>) = 2√2 × (-1/3) = -2√2/3

and so

csc(<em>θ</em>) = 1/sin(<em>θ</em>) = -3/(2√2)

6 0
3 years ago
Does anyone know the answer to any of these questions?
Ksju [112]
Thats for questions 3 - 8 that you didn't answer. I'm not quite sure how to answer the last two though.

7 0
4 years ago
Please help V'W'is a translation of VW Write the translation rule.
wel

Answer:

(x+11), (y+15)

Step-by-step explanation:

the point v gets translated 11 points to the right, so the translation is x+11.

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4 0
2 years ago
Which ordered pair makes the equation true 2x - 5y = -10
tino4ka555 [31]

With only one equation and no answer choices, there are an infinite number of possible values for x and y to make the equation true.

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