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3 years ago

Write an equation of the line containing the points (-6,19) and (-15,28)

2 answers:

4 0

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -6}}\quad ,&{{ 19}})\quad 
% (c,d)
&({{ -15}}\quad ,&{{ 28}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{28-19}{-15-(-6)}\implies \cfrac{28-19}{-15+6}
\\\\\\
\cfrac{9}{-9}\implies -1
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-19=-1(x-(-6))\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-19=-(x+6)$

kogti [31]3 years ago

4 0

(-6,19) (-15,28)

28-19/-15-(-6)= 9/-9= -1

19=(-1)(-6) + b
19= 6 +b
b= 13
Therefore:
y= -x + 13
Hope I helped :)

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Answer:

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