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3 years ago

Write an equation of the line containing the points (-6,19) and (-15,28)

2 answers:

4 0

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -6}}\quad ,&{{ 19}})\quad 
% (c,d)
&({{ -15}}\quad ,&{{ 28}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{28-19}{-15-(-6)}\implies \cfrac{28-19}{-15+6}
\\\\\\
\cfrac{9}{-9}\implies -1
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-19=-1(x-(-6))\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-19=-(x+6)$

kogti [31]3 years ago

4 0

(-6,19) (-15,28)

28-19/-15-(-6)= 9/-9= -1

19=(-1)(-6) + b
19= 6 +b
b= 13
Therefore:
y= -x + 13
Hope I helped :)

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PLEASE HELP URGENT!!!!!!!! NUMBER 46 AND 47!!!!!!!!!!!!!!

crimeas [40]

Answer:

46 is d I'm not sure for 47 but I think it's c not sure tho

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3 years ago

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Where’s the equation?

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3 years ago

A sample of 114 mortgages approved during the current year showed that 36 were issued to a single-earner family or individual. T

kodGreya [7K]

Answer:

a-1) Reject H0 if zcalc > 1.645

a-2) $z=\frac{0.316 -0.28}{\sqrt{\frac{0.28(1-0.28)}{114}}}=0.8561$

a-3) ii. False

b) ii. No

c) iii. n π > 10 and n(1 − π ) > 10

Step-by-step explanation:

1) Data given and notation

n=114 represent the random sample taken

X=36 represent the people that were issued to a single-earner family or individual

$\hat p=\frac{36}{114}=0.316$ estimated proportion of people that were issued to a single-earner family or individual

$p_o=0.28$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

(a-1) H0: π ≤ .28 versus H1: π > .28. Choose the right option. Reject H0 if zcalc > 1.645 Reject H0 if zcalc < 1.645 a b

We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.28.:

Null hypothesis: $p\geq 0.28$

Alternative hypothesis: $p < 0.28$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

The rejection zone would be on this case :

Reject H0 if zcalc > 1.645

Since is a right tailed test

(a-2) Calculate the test statistic. (Round intermediate calculations to 2 decimal places. Round your answer to 4 decimal places.) Test statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.316 -0.28}{\sqrt{\frac{0.28(1-0.28)}{114}}}=0.8561$

(a-3) The null hypothesis should be rejected.

False, since our calculated value is less than our critical value we Fails to reject the null hypothesis

(b) Is this a close decision?

False the calculated value is significantly less than the critical value so we FAIL to reject the null hypothesis with enough confidence.

(c) State any assumptions that are required.

In order to satisfy the conditions we need the following two requirements:

iii. n π > 10 and n(1 − π ) > 10

And are satisfied:

114*0.28=31.92>10

114(1-0.28)=82,08>10

7 0

3 years ago

A store has a 25\%25% off sale on coats. With this discount, the price of one coat is \$34.50$34.50. What is the original price

timama [110]

Answer:

$46

Step-by-step explanation:

A percent is a portion of 100. If we receive 25% off then we pay 75% of the price. 100%-25%=75%. $34.50 is 75% of the original price. We find the new price through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities. For example, we will compare percent over percent to an equal ratio of $ to $.

$\frac{75}{100} =\frac{34.50}{y}$