All categories

3 years ago

Which equation in point-slope form contains the points (8, 10) and (–4, 2)?

Mathematics

1 answer:

Gemiola [76]3 years ago

5 0

Y-10=2/3x(x-8) that is in point slope form

You might be interested in

Solve 240 = 6z + c for 'c'. show steps please

Lunna [17]

There are two ways to find or determine for the value of c. In the first method, we can use addition and subtraction to isolate the variable c from the other variables. In the second method, we can use the transposition of variables to isolate the variable c from the other variables.

So solving for the value of c:

Using 1st method: Addition and Subtraction

We are given:

240 = 6 z + c

Simply subtract 6 z on both sides:

240 – 6 z = 6 z + c – 6 z

Cancelling 6 z – 6 z on the right side:

240 – 6 z = c

c = 240 – 6 z

Using the 2nd method: Transposition

240 = 6 z + c

What we are going to do here is to simply transpose the variable 6 z from the right side to the left side of the equation so that we are left with c alone on the right side. Always remember that when we transpose, the symbol becomes opposite. That is:

240 + (- 6 z) = c

240 – 6 z = c

c = 240 – 6 z

6 0

4 years ago

288 times 66 =? Plz help

gtnhenbr [62]

19,008 I just used a calculator

4 0

3 years ago

Read 2 more answers

Enter the giveaway for points

Nookie1986 [14]

Answer:

Thxx for points how do I enter

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

How can 1% of 300 be used to determine 64% of 300? Enter your answers in the boxes to correctly complete the statement. 1% of 30

Ratling [72]

Answer:

1% of 300 is 3 so if you multiply that 3 by 64, you get 192 which is also 64% of 300

Step-by-step explanation:

.01 x 300 = 3

3 x 64 = 192

.64 x 300 = 192

4 0

2 years ago

Read 2 more answers

One uranium atom has a mass of 3.95 x 10^-22 grams.

creativ13 [48]

Remember
(ab)/(cd)=(a/c)(b/d)
and
$\frac{x^n}{x^m}=x^{n-m}$

1kg=1000g=1*10^3g
hmm, I estimate, 4 of them

x=number of attoms
mass of 1 times x=1*10^3
3.95*10^-22 times x=1*10^3
divide both sides by 3.95*10^-22
x= $\frac{1*10^3}{3.95*10^{-22}}= (\frac{1}{3.95} )( \frac{10^{3}}{10^{-22}} )$ = $0.25316*10^{25}$ = $2.5316*10^{24}$
a million has 9 zeroes
so 24 zeroes is alot that is a septillion, so there are 2.5316 septillion uranium atoms in 1kg

a. 4
b. underestimate

5 0

3 years ago