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3 years ago

Organic chemistry!!! Plz help

Chemistry

1 answer:

jasenka [17]3 years ago

3 0

Answer:

3) 2,2-dichloroheptane

Explanation:

2,2-dichloroheptane

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How much energy is required to raise the temperature of 10.6 grams of gaseous neon from

Alona [7]

Answer:

Approximately $1.95 \times 10^{2}\; \rm J$ .

Explanation:

Look up the specific heat of gaseous neon:

$c = 1.03 \; \rm J \cdot g^{-1} \cdot K^{-1}$ .

Calculate the required temperature change:

$\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K$ .

Let $m$ denote the mass of a sample of specific heat $C$ . Energy required to raise the temperature of this sample by $\Delta T$ :

$Q = c \cdot m \cdot \Delta T$ .

For the neon gas in this question:

$c = 1.03\; \rm J \cdot g^{-1}\cdot K^{-1}$ .
$m = 10.6\; \rm g$ .
$\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K$ .

Calculate the energy associated with this temperature change:

$\begin{aligned}Q &= c \cdot m \cdot \Delta T \\ &= 1.03\; \rm J \cdot g^{-1}\cdot K^{-1} \times 10.6\; \rm g \times 17.9\; \rm K \\ &\approx 1.95 \times 10^{2}\; \rm J\end{aligned}$ .

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3 years ago

Why does the hull of an ocean -going ship rust quickly?

stepan [7]

Metal rusts when it oxidized around moisture.

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2 years ago

A mixture of two or more kinds of molecules, evenly dispersed would be a(n)

Dvinal [7]

Azeotropic mixture. I think

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2 years ago

A 20.00 ml sample of a solution of sr(oh)2 is titrated to the equivalence point with 40.03 ml of 0.1159 n hcl. what is the molar

goblinko [34]

The molarity of Sr(OH)2 solution is = 0.1159 M

calculation
write the equation for reaction
that is, Sr(OH)2 +2HCl→ SrCl2 + 2 H2O

then finds the mole of HCl used

moles = molarity x volume
=40.03 x0.1159 = 4.639 moles

by use of mole ratio between Sr(OH)2 to HCL which is 1 :2 the moles of Sr(OH)2 is therefore = 4.639 x1/2 = 2.312 moles

molarity of Sr(OH)2 is = moles / volume

=2.312 /20 =0.1159 M

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3 years ago

Lye is a common ingredient in drain cleaning products. It is made of one atom of sodium, one atom of oxygen, and one atom of hyd

il63 [147K]

The answer would be NaOH

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3 years ago