Organic chemistry!!! Plz help

Newton's third law of motion is summarized as the law of action-reaction. For every action, there is an equal but opposite react

Fantom [35]

Answer:

When we stand on the floor, we apply a force on the floor surface in the downward direction and in return the floor also exerts an upward and equal force on us.

Explanation:

Newton' third law is vey famous and it states that for each and every action, there applies an equal but opposite reaction. Thus the action force and the reaction force always acts on pairs. But they does not contribute to the motion of the object.

One such example that illustrates the action and reaction force from Newton's law is when we stand on the floor we exert a force on the floor surface in downward direction. The floor surface also exerts an opposite and equal force on us in the upward direction.

7 0

3 years ago

A radioactive nuclide that is used for geological dating has an atomic number of 19 and mass number 40. Which is the symbol of t

Alina [70]

The mass number goes on top, and the atomic number goes on bottom.
Therefore, the answer is C:
40
K
19

7 0

4 years ago

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A sample of seawater contains 78.0 grams of NaCl in 2,025 mL of solution. If the molar mass of NaCl is 58.443 g/mol, what is the

DENIUS [597]

Answer:

that would be 0.659 M NaCl

4 0

3 years ago

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The reaction of NH3 and O2 forms NO and water. The NO can be used to convert P4 to P4O6, forming N2 in the process. The P4O6 can

posledela

Answer : The mass of $PH_3$ produced from the reaction is, 0.651 grams.

Explanation :

The chemical reactions used are:

(1) $4NH_3+5O_2\rightarrow 4NO+6H_2O$

(2) $6NO+P_4\rightarrow P_4O_6+3N_2$

(3) $P_4O_6+6H_2O\rightarrow 4H_3PO_4$

(4) $4H_3PO_4\rightarrow PH_3+3H_3PO_4$

First we have to calculate the moles of $NH_3$

$\text{Moles of }NH_3=\frac{\text{Mass of }NH_3}{\text{Molar mass of }NH_3}$

Molar mass of $NH_3$ = 17 g/mol

$\text{Moles of }NH_3=\frac{1.95g}{17g/mol}=0.115mol$

Now we have to calculate the moles of $NO$

From the balanced chemical reaction 1, we conclude that:

As, 4 moles of $NH_3$ react to give 4 moles of $NO$

So, 0.115 moles of $NH_3$ react to give 0.115 moles of $NO$

Now we have to calculate the moles of $P_4O_6$

From the balanced chemical reaction 2, we conclude that:

As, 6 moles of $NO$ react to give 1 moles of $P_4O_6$

So, 0.115 moles of $NO$ react to give $\frac{0.115}{6}=0.0192$ moles of $P_4O_6$

Now we have to calculate the moles of $H_3PO_4$

From the balanced chemical reaction 3, we conclude that:

As, 1 moles of $P_4O_6$ react to give 4 moles of $H_3PO_4$

So, 0.0192 moles of $P_4O_6$ react to give $0.0192\times 4=0.0768$ moles of $H_3PO_4$

Now we have to calculate the moles of $PH_3$

From the balanced chemical reaction 4, we conclude that:

As, 4 moles of $H_3PO_4$ react to give 1 moles of $PH_3$

So, 0.0768 moles of $H_3PO_4$ react to give $\frac{0.0768}{4}=0.0192$ moles of $PH_3$

Now we have to calculate the mass of $PH_3$

$\text{ Mass of }PH_3=\text{ Moles of }PH_3\times \text{ Molar mass of }PH_3$

Molar mass of $PH_3$ = 33.9 g/mole

$\text{ Mass of }PH_3=(0.0192moles)\times (33.9g/mole)=0.651g$

Therefore, the mass of $PH_3$ produced from the reaction is, 0.651 grams.

6 0

3 years ago

If 1.00 mol of an ideal monatomic gas initially at 74 K absorbs 100 J of thermal energy, what is the final temperature

PtichkaEL [24]

Answer:

T = 82 K

Explanation:

The computation of the final temperature is shown below;

Given that

T_0 denotes the initial temperature of the gas i.e. 74 K

T denotes the final temperature of the gas = ?

n denotes number of moles of monoatomic gas i.e. 1.00 mol

R denotes universal gas constant = 8.314

c denotes the heat capacity at constant volume i.e.

= (1.5) R = (1.5) (8.314)

= 12.5

Q denotes the Amount of heat absorbed i.e 100 J

We know that

Amount of heat absorbed is provided as

Q = n c (T - T_0)

100 = (1) (12.5) (T - 74)

T = 82 K

7 0

3 years ago