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s344n2d4d5 [400]
3 years ago
5

Organic chemistry!!! Plz help

Chemistry
1 answer:
jasenka [17]3 years ago
3 0

Answer:

3) 2,2-dichloroheptane

Explanation:

2,2-dichloroheptane

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A sealed container holding 0.0255 L of an ideal gas at 0.991 atm and 69 ∘ C is placed into a refrigerator and cooled to 43 ∘ C w
ANEK [815]

Answer:

The final pressure of the gas is 0.915atm

Explanation:

We have to apply the Charles Gay Lussac Law, where the pressure changes directly proportional to absolute T°

- No change in volume

- The same moles in both situations

P1 / T1  =  P2 / T2

0.991 atm / 342K = P2 / 316k

(0.991 atm / 342K) . 316K = P2

0.915 atm = P2

3 0
4 years ago
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What is the name of this unstable isotope from number 9?
raketka [301]

Is there a picture of the isotope or?- becaue I can’t help if I don’t have a visual.

6 0
3 years ago
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What part of the earth is made up of the tectonic plates? list and describe the motion of the three types of plate boundaries?
Naddika [18.5K]
The crust
1. divergent (moves away from each other)
2. convergent (moves towards each other)
3. transform (slides past each other)
3 0
3 years ago
The partial pressure of N2 in the air is 593 mm Hg at 1 atm. What is the partial pressure of N2 in a bubble of air a scuba diver
Evgen [1.6K]

Answer: Partial pressure of N_{2} at a depth of 132 ft below sea level is 2964 mm Hg.

Explanation:

It is known that 1 atm = 760 mm Hg.

Also,   P_{N_{2}} = x_{N_{2}}P

where,    P_{N_{2}} = partial pressure of N_{2}

                 P = atmospheric pressure

            x_{N_{2}} = mole fraction of N_{2}

Putting the given values into the above formula as follows.

      P_{N_{2}} = x_{N_{2}}P

    593 mm Hg = x_{N_{2}} \times 760 mm Hg

       x_{N_{2}} = 0.780

Now, at a depth of 132 ft below the surface of the water where pressure is 5.0 atm. So, partial pressure of N_{2} is as follows.

         P_{N_{2}} = x_{N_{2}}P

                  = 0.78 \times 5 atm \times \frac{760 mm Hg}{1 atm}

                  = 2964 mm Hg

Therefore, we can conclude that partial pressure of N_{2} at a depth of 132 ft below sea level is 2964 mm Hg.

8 0
3 years ago
Identify the mixture of powdered charcoal and powdered sugar and suggest a technique for separating their components
mihalych1998 [28]
A- Identify the mixture:
The mixture of powdered charcoal and powdered sugar is considered as a homogeneous mixture. This means that you cannot identify the components with naked eye as they are uniformly distributed in the mixture.

B- Separate components:
You ca separate the charcoal powder from the sugar powder using the following steps:
1- add water. Sugar will dissolve in water while charcoal won't.
2- filter the solution where the powdered charcoal will remain on the filter paper and the solution of powder will pass through.
3- boil the sugar solution (above 100 degrees celcius). The water will evaporate and the sugar will precipitate.
5 0
3 years ago
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