#6).
Every 1,000 mL makes 1 L
How many 1,000mL are there in 2,800 mL ?
That's division.
(2,800 mL) / (1,000 mL) = <em>2.8 L</em>
#7).
The 'perimeter' means the 'distance all the way around'.
You have to know that both sides of a rectangle are the same length,
and also the top and bottom are the same length.
So the perimeter of this rectangle is
(2 yd) + (4.5 yd) + (2.yd) + (4.5 yd) = 13 yd .
Oops. The problem wants to know the perimeter in feet.
So you have to know that each yard is the same as 3 feet.
In order to find the number of feet in 13 yards, you have to
take 3 feet 13 <em><u>times</u></em> .
(3 feet) times (13) = <em>39 feet .</em>
#8).
For this one, you have to know that every 36 inches makes 1 yard.
How many 36 inches are there in 48 inches ?
That's division.
(48 inches) / (36inches) = <em>1 and 1/2 yards</em> .
#9).
For this problem, you have to know how to handle a mixed number,
and you also have to know that there are 16 ounces in 1 pound.
Add up the fruit:
(3-1/2 pounds) + (4 pounds) + 2 pounds) = <em><u>9-1/2 pounds</u></em>
Now, remember that each pound is the same as 16 ounces. So if you
want to find the number of ounces in 9-1/2 pounds, you have to take
16 ounces 9-1/2 times .
(16 ounces) times (9-1/2) = <em>152 ounces</em>.
___________________________________
#10).
This one is just adding up some numbers. But after you finish doing that, you have to know that 1,000 meters is called '1 kilometer' .
Add up the distances that Omar ran:
(1,000 meters) + (1,625 meters) + (1,500 meters) = <em><u>4,125 meters</u></em>
The problem wants to know how many kilometers this is, so you have to figure out how many '1,000 meters' fit into 4,125 meters.
That's division.
(4,125 meters) / (1,000 meters) = <em>4.125 kilometers</em>
Answer:
118750 ml
Explanation:
The chemical equation for complete combustion of hexane is given as;
2C6H14 + 19O2 → 12CO2 + 14H2O
From the equation of the reaction;
2 mol of C6H14 reacts with 19 mol of O2
2 ml of C6H14 reacts with 19 ml of O2
2500 mL of C6H14 would react with x ml of O2
2 = 19
2500 = x
x = 2500 * 19 / 2 = 23750 ml
Since oxygen is 20% of air;
23750 = 20 / 100 * (Volume of air)
Volume of air = 23750 * 100 / 20 = 118750 ml
A reaction occurs between the two gases Chlorine monofluoride (ClF) and Fluorine (F₂) when they are added together and as a result of the reaction a compound named, Chlorine trifluoride (ClF₃) is formed.
The reaction which occurs by addition of Chlorine monofluoride (ClF) and Fluorine (F₂) is as follows -
ClF (g) + F₂ (g) = ClF₃ (l)
When one molecule of Chlorine monofluoride (ClF) reacts with one molecule of Fluorine (F₂) gas, both the gases react together to form one molecule of Chlorine trifluoride (ClF₃) which is a liquid. Therefore, the above reaction is already balanced.
Chlorine trifluoride (ClF₃) is a greenish-yellow liquid which acts as an important fluorinating agent and is also an interhalogen compound (compounds that are formed by mixing two different halogen compounds together). Other than it's liquid state ClF₃ also can exist as a colorless gas. This compound ClF₃ is a very toxic, very corrosive and powerful oxidizer used as an igniter and propellent in rockets.
Learn more about Chlorine monofluoride (ClF) here-
brainly.com/question/17129650
#SPJ4
Answer:
[H2] = 0.0692 M
[I2] = 0.182 M
[HI] = 0.826 M
Explanation:
Step 1: Data given
Kc = 54.3 at 430 °C
Number of moles hydrogen = 0.714 moles
Number of moles iodine = 0.984 moles
Number of moles HI = 0.886 moles
Volume = 2.40 L
Step 2: The balanced equation
H2 + I2 → 2HI
Step 3: Calculate Q
If we know Q, we know in what direction the reaction will go
Q = [HI]² / [I2][H2]
Q= [n(HI) / V]² /[n(H2)/V][n(I2)/V]
Q =(n(HI)²) /(nH2 *nI2)
Q = 0.886²/(0.714*0.984)
Q =1.117
Q<Kc This means the reaction goes to the right (side of products)
Step 2: Calculate moles at equilibrium
For 1 mol H2 we need 1 mol I2 to produce 2 moles of HI
Moles H2 = 0.714 - X
Moles I2 = 0.984 -X
Moles HI = 0.886 + 2X
Step 3: Define Kc
Kc = [HI]² / [I2][H2]
Kc = [n(HI) / V]² /[n(H2)/V][n(I2)/V]
Kc =(n(HI)²) /(nH2 *nI2)
KC = 54.3 = (0.886+2X)² /((0.714 - X)*(0.984 -X))
X = 0.548
Step 4: Calculate concentrations at the equilibrium
[H2] = (0.714-0.548) / 2.40 = 0.0692 M
[I2] = (0.984 - 0.548) / 2.40 = 0.182 M
[HI] = (0.886+2*0.548) /2.40 = 0.826 M
