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Mariana [72]
3 years ago
7

A sealed container holding 0.0255 L of an ideal gas at 0.991 atm and 69 ∘ C is placed into a refrigerator and cooled to 43 ∘ C w

ith no change in volume. Calculate the final pressure of the gas.
Chemistry
2 answers:
Kobotan [32]3 years ago
5 0

Answer: Final pressure of the gas is 0.916atm

Explanation: Using Charles law formula. P1V1T2 = P2V2T1

Where P1 = 0.991atm, V1 = 0.0255L, T1 = 69°C = 273+69= 546.15 , P2 = x, V2 = 0.0255L, T2 = 43°C = 273+43= 316.15K.

Solution.

Substituting all the parameters into the equation

P1V1T2=P2V2T1,

we get,

0.991×0.0255×316.15 = P2 × 0.0255 × 546.15

P2 = 0.916atm

ANEK [815]3 years ago
3 0

Answer:

The final pressure of the gas is 0.915atm

Explanation:

We have to apply the Charles Gay Lussac Law, where the pressure changes directly proportional to absolute T°

- No change in volume

- The same moles in both situations

P1 / T1  =  P2 / T2

0.991 atm / 342K = P2 / 316k

(0.991 atm / 342K) . 316K = P2

0.915 atm = P2

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klio [65]
  Mass  of  electrons  are not  included when  calculating  the  atomic  mass  of   element.  Atomic  mass  of  the   element  is  equal  to   proton  +  neurons.  Example  the    the  mass  number  of  Nitrogen can   be  calculated as      7 protons  +  7  neutrons  to  give 14 .  thus  nitrogen  has  a  mass  number  of  14
4 0
3 years ago
How many protons, neutrons, and electrons does sodiums neutral atom have? Plz help.
rusak2 [61]

Answer:

So for your question, the Periodic Table tells us that sodium has an Atomic Number of 11, so there are 11 protons and 11 electrons. The Periodic Table tells us that sodium has an Atomic Mass of ≈23. So there are 23 - 11 = 12 neutrons.

Explanation:

3 0
3 years ago
A sample of 8.11 g 8.11 g of solid calcium hydroxide is added to 38.0 mL 38.0 mL of 0.410 M 0.410 M aqueous hydrochloric acid. W
Andrews [41]

Answer:

The balanced chemical equation :

Ca(OH)_2(s)+2HCl(aq)\rightarrow CaCl_2(aq)+2H_2O(l)

Explanation:

When calcium hydroxide reacts with hydrochloric acid it gives calcium chloride and water as a products. The chemical equation is given as:

Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O

According to question, solid calcium hydroxde is added to 38.0 mL of 0.410 M of HCl solution, so the chemical equation can be written as:

Ca(OH)_2(s)+2HCl(aq)\rightarrow CaCl_2(aq)+2H_2O(l)

According to stoichiometry, when 1 mole of solid calcium hydroxide reacts with 1 mole of hydrochloric acid to gives 1 mole of aqueous calcium chloride and 1 mole of water.

4 0
3 years ago
Which pair of elements have the same valence electronic configuration of np³?
Dennis_Churaev [7]

Answer:

(c) P and Sb

Explanation:

We can determine the number of valence electrons of an element:

  • If it belongs to Groups 1 and 2, the number of valence electrons is equal to the number of group and the differential electron occupies the s subshell.
  • If it belongs to the groups 13-18, the number of valence electrons is equal to: "Number of group - 10" and the differential electron occupies the p subshell.

Which pair of elements have the same valence electronic configuration of np³?

(a) O and Se. NO. They belong to the group 16 and the valence electron configuration is ns² np⁴.

(b) Ge and Pb. NO. They belong to the group 14 and the valence electron configuration is ns² np².

(c) P and Sb. YES. They belong to the group 15 and the valence electron configuration is ns² np³.

(d) K and Mg. NO. They belong to the groups 1 and 2 and the valence electron configuration is ns¹ and ns².

(e) Al and Ga. NO. They belong to the group 13 and the valence electron configuration is ns² np¹.

5 0
3 years ago
Biacetyl, the flavoring that makes margarine taste "just like butter," is extremely stable at room temperature, but at 200°C it
Sholpan [36]

Answer:

3.91 minutes

Explanation:

Given that:

Biacetyl breakdown with a half life of 9.0 min after undergoing first-order reaction;

As we known that the half-life for first order is:

t__{1/2}}= \frac{0.693}{k}

where;

k = constant

The formula can be re-written as:

k = \frac{0.693}{t__{1/2}}

k = \frac{0.693}{9.0 min}

k = 0.077 min^{-1}

Let the initial amount of butter flavor in the food be (N_0) = 100%

Also, the amount of butter flavor retained at 200°C (N_t)= 74%

The rate constant k = 0.077 min^{-1}

To determine how long can the food be heated at this temperature and retain 74% of its buttery flavor; we use the formula:

\frac{N_t}{N_0}= -kt

t = - (\frac{1}{k}*In\frac{N_t}{N_0}  )

Substituting our values; we have:

t = - (\frac{1}{0.077}*In\frac{74}{100}  )

t = 3.91 minutes

∵ The time needed for the food to be heated at this temperature and retain 74% of its buttery flavor is 3.91 minutes

4 0
3 years ago
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