Divide 3x^2+6 by 3x-3
2 answers:
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THE ANSWER IS: D. y=-3x+11
when two lines are parallel, they share the same slope, which is -3
then plug in the given point into slope intercept form then solve for standard form
when two lines are parallel, they share the same slope, which is -3
then plug in the given point into slope intercept form then solve for standard form
If a = 4 and d = 3,
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Answer: The general equation for the nth term is 3n + 1.
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Answer:
The length of the rectangle is 11 inch and its width is 8 inch.
Step-by-step explanation:
Given:
Rectangle and rectangle
.
Let the width of the rectangle be 'x' inch.
Its length = '(x+3)' inch
Area of the rectangle =
⇒ =
Now for rectangle its width is decreased by 1 inch and length is doubled,the area
will increased by 66 sq-inch.
So,
According to the question.
⇒ Area of rectangle with width '(x-1)' and length '2(x+3)'='(2x+6)' .
⇒
Plugging the values of in terms of
.
⇒
Plugging =
into the equation.
⇒
⇒
⇒
⇒
Now using quadratic formula we can find the value of 'x'.
Quadratic formula, (x)=
x= -9 and x= 8
Discarding the negative value.
Our width = 'x' = 8 inches.
So the length of the rectangle = 11 inches and width of the rectangle = 8 inches.