The x-axis serves as a horizontal asymptote for all exponential functions. Exponential functions are of the form f(x) = ax . The domain consists of all real numbers. However, the range only consists of all numbers greater than zero. This is because no matter how large x gets, the graph will shoot upwards towards infinity. If x becomes a negative, we know that we will get f(x) = 1/a2 . The larger the negative number, the closer the function approaches zero. So, for exponential functions we will always have that restriction that the range will only include positive numbers. I hope this answers your question. I believe the statement is true.
Answer:
Step-by-step explanation:
The answer is 441!
626
-185
———
441
Let's named variables as M,J and R
The equation is M+J+R=74
We will represent M with J => M=J+6 and R=2J
when we replace in the equation we get
J+6+J+2J=74 => 4J=74-6 => 4J=68 => J=68/4 = 17
J=17 => M=6+17 => M=23 and R=2* 17 => R=34
Final answer is
Juan served 17 orders
Melissa served 23 orders and
Rafael served 34 orders
Good luck!!!!
Answer:
B) (−1, 3)
Step-by-step explanation:
The standard form of a quadratic function is
y = ax² + bx + c
The vertex form of a parabola is
y = a(x - h)² + k
where (h, k) is the vertex of the parabola.
h = -b/(2a) and k = f(h)
In your equation, ƒ(x) = −3x² − 6x
a = -3; b = -6; c = 0
Calculate h
h = -(-6)/2(-3)]
h = 6/(-6)
h = -1
Calculate k
k = -3(-1)² -6(-1)
k = -3 + 6
k = 3
So, h = -1, k = 3, a = -3
The vertex form of the equation is f(x) = -3(x + 1)² + 3.
The vertex is at (-1, 3).
The figure below shows the graph of ƒ(x) = −3x² − 6x with the vertex
at (-1, 3).
