Determine if -5 is a solution for the inequality 1-2d-9

Rank and alice are penguins. at birth, frank's beak was 1.95 inches long, while alice's was 1.50 inches long. homework help ✎ fr

miskamm [114]

F for Frank, A or Alice. F(initial)=1.95 inches A(initial)=1.50 inches Frank's equation at .25 inches per year and t representing year variable. F=1.95+.25t Alice's equation at .40 inches per year and t representing year variable. A=1.5+.40t To figure out how old they will be when their beaks are the same lengths set the equations equal to eachother as the equations are length. 1.95+.25t=1.5+.40t .45=.15t t=3 years

5 0

2 years ago

A density curve for all the possible ages between 0 years and 100 years is in the shape of a triangle. What is the height of the

yawa3891 [41]

Hello there.

A density curve for all the possible ages between 0 years and 100 years is in the shape of a triangle. What is the height of the triangle?

Answer: D

8 0

3 years ago

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part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.

Nat2105 [25]

Answer: $\bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}$

Step-by-step explanation:

Pythagorean Theorem is: a² + b² = c² , where "c" is the hypotenuse

$9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}$

Note: 4² + (8√2)² = hypotenuse² → hypotenuse = 12

$10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}$

Note: 12² + opposite² = 20² → opposite = 16

$11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: adjacent² + 5² = 6² → adjacent = √11

$12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}$

Note: adjacent² + 7² = (13√2)² → adjacent = 17

5 0

3 years ago

A pilot can travel for 140 miles with the wind in the same amount of time as 360 miles against the wind. Find the speed of the w

quester [9]

Answer:

-88 mph

Step-by-step explanation:

We can use the relation ...

time = distance/speed

to compare the times in the two directions.

$\dfrac{140}{200+w}=\dfrac{360}{200-w}\\\\140(200-w)=360(200+w)\\\\200(140-360)=w(360+140)\\\\w=\dfrac{200(-220)}{500}=-88 \quad\text{miles per hour}$

The wind speed is -88 miles per hour.

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The problem statement tells us the travel is slower with the wind than against the wind. Hence "with the wind" must be subtracting from the net speed. That is, the wind speed is negative.

4 0

3 years ago

To create an entry code, you must first choose 3 letters and then, 6 single-digit numbers. How many different entry codes can

Anettt [7]

Well, you would use factorization for this, which would be MORE than 54 different codes! :D

7 0

3 years ago

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