it is over 32 degrees Fahrenheit (freezing), and below 120 degrees Fahrenheit (boiling)
The Chemical fomulla for Zinc Phosphate
Zn3(PO4)2
Answer:
Q = 1360.248 j
Explanation:
Given data:
Mass of brass = 298.3 g
Initial temperature = 30.0°C
Final temperature = 150°C
Specific heat capacity of brass = 0.038 J/g.°C
Heat absorbed = ?
SOLUTION:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 150°C - 30.0°C
ΔT = 120°C
Q = 298.3 g × 0.038 J/g.°C × 120°C
Q = 1360.248 j
Answer:
In this case, a neutral atom with 12 protons will have 12 electrons. On the periodic table, the atom with 12 protons is magnesium, which is in group 2 . Therefore, it will most likely lose 2 electrons to have 10 electrons, and form a noble gas configuration. So, magnesium becomes Mg2+ .
A. Condensation
when warm air hits the cold<span> surface it reaches its dew point and condenses</span>
