The largest mass silver chloride is precipitated when excess silver ions are added to 30.0cm3 of 0.30M iron(III) chloride solution.
<h3>What is a precipitation reaction?</h3>
A precipitation reaction is a reaction in which an insoluble substance is obtained when two solutions are mixed together as a result of one of the products of the reaction being insoluble in water.
Silver chloride is an insoluble salt that will precipitate when a single silver salt is added to a soluble chloride salt.
In the above, the largest mass silver chloride is precipitated when excess silver ions are added to 30.0cm3 of 0.30M iron(III) chloride solution since iron (iii) chloride is a weak electrolyte.
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Atomic number refers to the number of protons within the nuclei of an element's atoms (and therefore the number of electrons) while mass number refers to the number of protons and neutrons within the nucleus.
If they are in the same row they have the same number of outer electrons on the same main shell also known as valence electrons
if they are in the same column they have the same number of valence electrons but on different main shells
Because K and Cl have such a large disparity in their electronegativities, KCl is a bipolar ionic molecule.
<h3>What exactly are polar and nonpolar bonds?</h3>
Polar covalent bonds develop when the distribution of electrons among atoms is uneven, whereas nonpolar side chains develop when the distribution of electrons is more even. The reason for the unequal sharing of electrons is because the atoms receiving them have various electronegativities.
<h3>How are polar bonds created?</h3>
Whenever a single pair of electrons is not shared equally, a polar molecule bond is created. This is caused by the electronegativity difference between the two elements. An unit of h as well as an unit of bromine share a pair of electrons, but not evenly.
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Answer:
The solubility of the mineral compound X in the water sample is 0.0189 g/mL.
Explanation:
Step 1: Given data
The volume of water sample = 46.0 mL.
The weight of the mineral compound X after evaporation, drying, and washing = 0.87 g.
Step 2: Calculate the solubility of X in water
46.00 mL of water sample contains 0.87 g of the mineral compound X.
To calulate how many grams of the mineral compound 1.0 mL of water sample contains:
0.87 g/46.0 mL = 0.0189 g.
This means the solubility of the mineral compound X in the water sample is 0.0189 g/mL.
