I think the answer is B. 150 i may be wrong though
Answer:
trapezium................
Answer:
- 33 1/3 liters of 30%
- 16 2/3 liters of 45%
Step-by-step explanation:
Let x represent the liters of 45% solution needed. Then the amount of HCl in the mix is ...
0.45x +0.30(50 -x) = 0.35(50)
0.15x = 0.05(50) . . . . . simplify, subtract 0.30(50)
x = (0.05/0.15)(50) = 50/3 = 16 2/3 . . . liters of 45% HCl
33 1/3 liters of 30% and 16 2/3 liters of 45% HCl are needed.
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<em>Comment on the solution</em>
You may notice that the general solution to a mixture problem of this sort is that the fraction of the mix that is the highest contributor is ...
(mix % - low %) / (high % - low %) = (.35 -.30) / (.45 -.30) = .05/.15 = 1/3
Lets find out...
our fraction is 1/2.....
when the numerator is increased by 20%......1 + 0.20(1) = 1.2
when the denominator is increased by 50%....2 + 0.50(2) = 3
1/2 = 0.5....original fraction
1.2 / 3 = 0.4.....increased fraction
decrease = (original number - new number) / original number...* 100
= (0.5 - 0.4) / 0.5...* 100
= (0.1 / 0.5)....* 100
= 0.2 * 100
= 20% decrease <====