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kiruha [24]
2 years ago
10

Kim's softball team is playing in the championship game. They are losing by a score of 1 7 1717 to 6 66. There are 4 44 innings

to go. Kim wants to know how many runs her team needs per inning to win the game if the other team does not score. (Each run is worth 1 11 point.) Let r rr represent the number of runs per inning. Assume that the team scores the same number of runs per inning, and write an inequality to determine the number of runs per inning needed to win the game.
Mathematics
2 answers:
Furkat [3]2 years ago
7 0

Answer:

4r+6 > 17, and they would need at least 3 runs per inning.

Step-by-step explanation:

Letting r represent the number of runs per inning, for 4 innings, we have 4r.

The team already has 6 runs; this means we add the additional runs to this:

4r+6

The team wants to score more than the other team; this means they need more than 17:

4r+6 > 17

To solve this, subtract 6 from each side:

4r+6-6 > 17-6

4r > 11

Divide both sides by 4:

4r/4 > 11/4

r > 2.75

We can't have a portion of a run, so this means there will be at least 3 runs per inning.

irga5000 [103]2 years ago
6 0
The inequality is
6+4r>17
The miminum number of runs per inning is
3.
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There are 7 chairs in each row length.
Step-by-step explanation:
Let number of chairs in 1 row be 'x'.
Let total number of chairs be 'y'.
Given:
Hue can form 6 rows of a given length with 3 chairs left over.
It means that Total number of chairs is equal to chairs in 1 rows multiplied by number of rows which is 6 plus number of chairs which is left which is 3.
Framing in equation form we get.

Also Given:
Hue can form 8 rows of that same length if she gets 11 more chairs.
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Framing in equation form we get.

From equation 1 and equation 2 we can say that L.H.S is same.
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Combining like terms we get;

Using Subtraction and Addition property we get;

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Hence there are 7 chairs in each row length.
8 0
2 years ago
How can we define the radius of a circumference?
UkoKoshka [18]
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8 0
2 years ago
a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei
Masteriza [31]

Answer:

The weight of a small box  = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box  = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) =  5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) =  3 n

Here,   3 large boxes +  5 small boxes =  of 123 kilograms

⇒ 5  m + 3 n = 123   .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) =  2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) =  12 n

Here,   12 large boxes +  2 small boxes =  249 kilograms

⇒ 2 m+ 12 n = 249   .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5  m + 3 n = 123     x (2)

2 m+ 12 n = 249     x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n =  -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5  m + 3 n = 123

So, 5 m = 123  -3 (18.5)  = 123 - 55.5 =  67.5

⇒  m = 13.5

Hence,  the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg  = 18.5 kg

8 0
3 years ago
3.75<br>divided by 25<br>round off to the nearest rand​
sattari [20]

Answer:

0.15 is the answer

Step-by-step explanation:

7 0
2 years ago
3. To make green paint, mix 3 parts of blue to 4 parts of yellow. Does the table below show the same ratio
expeople1 [14]
No
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6÷7 ≈ .8571
These ratios are not the same.
5 0
2 years ago
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