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Vlada [557]
3 years ago
12

A rich woman deposits a whole number of dollars x in her bank. The next time she deposits y dollars (still a whole number). Each

subsequent deposit is the sum of the two previous deposits. Her 5th deposit was only $90, but her 10th deposit is exactly one thousand dollars. Find x and y first, then answer the question. Show your work.
What is the total amount of money in the bank?
Mathematics
1 answer:
grin007 [14]3 years ago
5 0

Answer:

x = 12

y = 22

Total amount = $2596

Step-by-step explanation:

First let's find the value of each deposit until the 10th in relation to x and y:

1st: x

2nd: y

3rd: x + y

4th: x + 2y

5th: 2x + 3y

6th: 3x + 5y

7th: 5x + 8y

8th: 8x + 13y

9th: 13x + 21y

10th: 21x + 34y

Now, we can write a system with two equations and two variables:

2x + 3y = 90

21x + 34y = 1000

From the first equation: x = (90 - 3y)/2

Using this value of x in the second equation, we have:

21*(90 - 3y)/2 + 34y = 1000

945 - 31.5y + 34y = 1000

2.5y = 55

y = 22

Now we can find x:

x = (90 - 3*22)/2 = 12

Now, summing all the deposits, we have a total of 55x + 88y, which is equal to 55*12 + 88*22 = $2596

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Hey can you help me answer this question by giving me the answer?
Leto [7]

The value of f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Given a function f(x)=4-2x+6x^{2}.

We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.

Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6a^{2} (By just putting x=a).

f(a+h)==4-2(a+h)+6(a+h)^{2}

=4-2a-2h+6(a^{2} +h^{2} +2ah)

=4-2a-2h+6a^{2} +6h^{2} +12ah

=6a^{2} +6h^{2}-2a-2h+12ah

[f(a+h)-f(a)]/h=[6a^{2} +6h^{2}-2a-2h+12ah-(4-2a+6a^{2} )]/h

=(6a^{2} +6h^{2} -2a-2h+12ah)/h

=(6h^{2} -2h+12ah)/h

=6h+12a-2.

Hence the value of function f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Learn more about function at brainly.com/question/10439235

#SPJ1

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kow [346]
3.9 and 5.3, when rounded off and mult. together, produce the product 20.
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3.9*5.3 = 20.67 by calculator.
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3 years ago
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