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Vlada [557]
3 years ago
12

A rich woman deposits a whole number of dollars x in her bank. The next time she deposits y dollars (still a whole number). Each

subsequent deposit is the sum of the two previous deposits. Her 5th deposit was only $90, but her 10th deposit is exactly one thousand dollars. Find x and y first, then answer the question. Show your work.
What is the total amount of money in the bank?
Mathematics
1 answer:
grin007 [14]3 years ago
5 0

Answer:

x = 12

y = 22

Total amount = $2596

Step-by-step explanation:

First let's find the value of each deposit until the 10th in relation to x and y:

1st: x

2nd: y

3rd: x + y

4th: x + 2y

5th: 2x + 3y

6th: 3x + 5y

7th: 5x + 8y

8th: 8x + 13y

9th: 13x + 21y

10th: 21x + 34y

Now, we can write a system with two equations and two variables:

2x + 3y = 90

21x + 34y = 1000

From the first equation: x = (90 - 3y)/2

Using this value of x in the second equation, we have:

21*(90 - 3y)/2 + 34y = 1000

945 - 31.5y + 34y = 1000

2.5y = 55

y = 22

Now we can find x:

x = (90 - 3*22)/2 = 12

Now, summing all the deposits, we have a total of 55x + 88y, which is equal to 55*12 + 88*22 = $2596

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klasskru [66]

Answer:

221

Step-by-step explanation:

Day 8 is the first day of the second week.

Day 21 is the last day of week 3.

We need to know the n umber of bicycles made from t = 1 to t = 3

The function is b(t) = 110 + 0.5t^2 - 0.9t, where t is in weeks.

We need to integrate the function with the limits of 1 to 3.

\int_{1}^{3} (110 + 0.5t^2 - 0.9t) dt

\int_{1}^{3} (110 + \dfrac{t^2}{2} - \dfrac{9t}{10}) dt

= 110t + \dfrac{t^3}{6} - \dfrac{9t^2}{20} \Biggr|_{1}^{3}

= 330.45 - 109.72

= 220.7333

Answer: 221

3 0
3 years ago
A random variable X follows the uniform distribution with a lower limit of 670 and an upper limit of 750.a. Calculate the mean a
DENIUS [597]

You can compute both the mean and second moment directly using the density function; in this case, it's

f_X(x)=\begin{cases}\frac1{750-670}=\frac1{80}&\text{for }670\le x\le750\\0&\text{otherwise}\end{cases}

Then the mean (first moment) is

E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x\,\mathrm dx=710

and the second moment is

E[X^2]=\displaystyle\int_{-\infty}^\infty x^2\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x^2\,\mathrm dx=\frac{1,513,900}3

The second moment is useful in finding the variance, which is given by

V[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2=\dfrac{1,513,900}3-710^2=\dfrac{1600}3

You get the standard deviation by taking the square root of the variance, and so

\sqrt{V[X]}=\sqrt{\dfrac{1600}3}\approx23.09

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I’ll give brainliest if u answer within 30 mins
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Answer:

96.7 maybe or 6.75 or 5.67 or even 56.77

Step-by-step explanation:

EZ

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If PS = 2x + 18 and QR = 5x - 9, solve for x.
Alexxx [7]

Answer:

2x+18+5x-9

2x+5x18-9

<u>7</u><u>x</u>+<u>9</u>

7. 7

x= 1.4

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