Does anyone know how to solve this?

Rabies is a viral disease of mammals transmitted through the bite of a rabid animal. The virus infects the central nervous syste

lisabon 2012 [21]

Answer:

(a) The value of x is 0.30.

(b) The probability that a reported case of rabies is not a raccoon is 0.45.

(c) The probability that a reported case of rabies is either a bat or a fox is 0.15.

Step-by-step explanation:

Denote the events as follows:

R = reported case of rabies is a raccoon

F = reported case of rabies is a fox

B = reported case of rabies is a bat

O = reported case of rabies is a some other animal.

The data provided is:

P (R) = 0.55

P (F) = 0.11

P (B) = 0.04

P (O) = x.

(a)

A property of a probability distribution is that the sum of all individual properties is 1.

That is, $\sum P(X)=1$

Compute the value of x as follows:

$\sum P(X)=1\\P(R)+P(F)+P(B)+P(O)=1\\0.55+0.11+0.04+x=1\\0.70+x=1\\x=1-0.70\\x=0.30$

Thus, the value of x is 0.30.

(b)

The probability of the complement of an event is the probability of its not happening.

$P(A^{c})=1-P(A)$

Compute the probability that a reported case of rabies is not a raccoon as follows:

$P(R^{c})=1-P(R)\\=1-0.55\\=0.45$

Thus, the probability that a reported case of rabies is not a raccoon is 0.45.

(c)

Compute the probability that a reported case of rabies is either a bat or a fox as follows:

$P(B\cup F)=P(B)+P(F)\\=0.11+0.04\\=0.15$

Thus, the probability that a reported case of rabies is either a bat or a fox is 0.15.

4 0

3 years ago

Aaron’s room has a perimeter of 96 feet. The length of the room is 23 feet. How wide is Aaron’s room?

SIZIF [17.4K]

Answer:

The length is also 25 feet.

Step-by-step explanation:

23+23+25+25=96

5 0

3 years ago

Read 2 more answers

Margaret wants to cover a footrest in the shape of a rectangular prism with cotton fabric. The footrest is 18 in. 12 in. 10 in.

user100 [1]

Answer:

No, she cannot completely cover the footrest.

Step-by-step explanation:

First of all, we need to find the total surface area of the prism to be covered using the cotton cloth

the total surface area of the prism is

A = 2wl + 2lh + 2hw,

l is the length of the prism = 18 in,

w= width of the prism = 12 in,

h is the height of the prism = 10 in

hence $A = 2(12 \times 18 ) + 2(18 \times 10) + 2(10 \times 12)=1032in^{2}$

We need to convert the area of the fabric to be in the same unit as that of the prism

Area of cotton fabric = $1 yd^{2}= 1296 in ^{2}$

since the surface area of the foot rest is more than the area of fabric she has, she cannot completely cover the footrest

6 0

3 years ago

Read 2 more answers

<2 and ___ are vertical angles. <2 and ___ or ___ are a linear pair help me pls.

Lena [83]

It should be noted that angle 2 and angle 1 are vertical angles and angle 2 and angle 5 are linear pair.

<h3>How to illustrate the information?</h3>

When two lines cross at a point, vertical angles are created. They are always on an equal footing. In other words, four angles are created anytime two lines cross or intersect. It is evident that two opposed angles are equal and are referred to as vertical angles.

When two lines cross at one point, a linear pair of angles is created. If the angles follow the intersection of the two lines in a straight line, they are said to be linear. A linear pair's total angles are always equal to 180°. These are also referred to as additional angles.

Therefore, it should be noted that angle 2 and angle 1 are vertical angles and angle 2 and angle 5 are linear pair.

Learn more about vertical angle on:

brainly.com/question/14362353

#SPJ1

7 0

1 year ago

Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
\\\\\\
\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
\\\\\\
\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

2 years ago