Answer:
Explanation:
The given equation is :
(30 pts) A simply supported beam with a span L=20 ft and cross sectional dimensions: b=14 in; h=20 in; d=17.5 in. is reinforced
with tension steel As=5 in2 . The beam supports a uniformly distributed dead load (including its own weight) DL=2.2 kips/ft and a uniformly distributed live load LL=1.8 kips/ft. The properties of the materials are as follows: f’c=4000 psi, steel fy=60,000 psi. Calculate the long-term deflections in the beam after five years.
1 answer:
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Answer:
The power developed by engine is 167.55 KW
Explanation:
Given that
Mean effective pressure = 6.4 bar
Speed = 2000 rpm
We know that power is the work done per second.
So
We have to notice one point that we divide by 120 instead of 60, because it is a 4 cylinder engine.
P=167.55 KW
So the power developed by engine is 167.55 KW