<u>Explanation:</u>
Task 1 time period = 200ms, Task 2 time period = 300ms
Task ticked =
→ 5 times
Task 2 ticked =
→ 3 times
At 600 ms → 200ms 200ms 200ms
300ms → ![\frac{30ms}{60ms}](https://tex.z-dn.net/?f=%5Cfrac%7B30ms%7D%7B60ms%7D)
Largest time period = H.C.M of (200ms, 300ms)
= 600ms
Answer:
a) W = 25.5 lbf
b) W = 150 lbf
Explanation:
Given data:
Mass of astronaut = 150 lbm
local gravity = 5.48 ft/s^2
a) weight on spring scale
it can be calculated by measuring force against local gravitational force which is equal to weight of body
W = mg
![W = (150 \times 5.48)\times \frac{1 lbm}{32.32 lbm. ft/s^2} = 25.5 lbf](https://tex.z-dn.net/?f=W%20%3D%20%28150%20%5Ctimes%205.48%29%5Ctimes%20%5Cfrac%7B1%20lbm%7D%7B32.32%20lbm.%20ft%2Fs%5E2%7D%20%3D%2025.5%20lbf)
b) As we know that beam scale calculated mass only therefore no change in mass due to variation in gravity
thus W= 150 lbf
Answer:
D
Explanation:
took test failed question D is the right answer
Answer:
Communication is simply the act of transferring information from one place, person or group to another. Every communication involves (at least) one sender, a message and a recipient.
Explanation:
Answer:
F = 0.0022N
Explanation:
Given:
Surface area (A) = 4,000mm² = 0.004m²
Viscosity = µ = 0.55 N.s/m²
u = (5y-0.5y²) mm/s
Assume y = 4
Computation:
F/A = µ(du/dy)
F = µA(du/dy)
F = µA[(d/dy)(5y-0.5y²)]
F = (0.55)(0.004)[(5-1(4))]
F = 0.0022N