Answer:
Flow velocity
50.48m/s
Pressure change at probe tip
1236.06Pa
Explanation:
Question is incomplete
The air velocity in the duct of a heating system is to be measured by a Pitot-static probe inserted into the duct parallel to the flow. If the differential height between the water columns connected to the two outlets of the probe is 0.126m, determine (a) the flow velocity and (b) the pressure rise at the tip of the probe. The air temperature and pressure in the duct are 352k and 98 kPa, respectively
solution
In this question, we are asked to calculate the flow velocity and the pressure rise at the tip of probe
please check attachment for complete solution and step by step explanation
Answer:
i think it is D tell me if its wrong
Explanation:
Answer:
The voltage needed to accelerate the electron beam is 2.46 x 10^16 Volts
Explanation:
The rate of electron flow is given as:
q = 1015 electrons per second
The total current is given by:
Total Current = (Rate of electron flow)(Charge on one electron)
Total Current = I = (1015 electrons/s)(1.6 x 10^-19 C/electron)
I = 1.624 x 10^-16 A
Now, we know that electric power is given as:
Electric Power = Current x Voltage
P = IV
V = P/I
V = 4 W/1.624 X 10^-16 A
<u>V = 2.46 x 10^16 Volts</u>
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