Cho hai mặt cầu đồng tâm O tích điện đều. Bán kính của hai mặt cầu lần lượt là R1 và R2 (R2>R1). Điện tích mặt trong là q và
1 answer:
You might be interested in
Check attached photo
Check attached photo
Answer:
(a) the compression of the spring when the block comes to rest is 4cm
(b) speed of the block is 0.427 m/s
Explanation:
Given;
mass of the block, m = 1.6 kg
spring constant, k = 902 N/m
initial speed of the block, v₀ = 0.95 m/s
(a) the compression of the spring when the block comes to rest
when the block comes to rest, the final speed, vf = 0
Apply the law of conservation of energy;
¹/₂kx² = ¹/₂mv₀²
kx² = mv₀²
x = 4 cm
(b) speed of the block
Apply the law of conservation of energy;
¹/₂mv² = ¹/₂kx²
mv² = kx²
Answer:
78.4 kg
225.792 J
Explanation:
= Mass of person = 78.4 kg
= Mass of canister = 0.005 kg
= Initial Velocity of person = 0 m/s
= Initial Velocity of canister = 3.6 m/s
= Final Velocity of person = 2.4 m/s
= Final Velocity of canister = 1.2 m/s
In this system the linear momentum is conserved
The mass of the canister is 78.4 kg
Kinetic energy is given by
The energy lost in the collision is 225.792 J