1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Naya [18.7K]
3 years ago
11

What is the factored form of this trinomial?

Mathematics
1 answer:
Lapatulllka [165]3 years ago
3 0

Answer:

(x=1)(2x+1)(2x-1)^2(x-1)^2

Step-by-step explanation:

You might be interested in
the sum of three numbers is 15. the second number is double the first. the third number is 5 less than the first. what are the t
tigry1 [53]

Hello from MrBillDoesMath!

Answer:

5, 10, 0

Discussion:

Let "f" be the first number. Then the questions tells us that

f + 2f  + (f-5) = 15           =>

f + 2f + f - 5 = 15            => add 5 to both sides

4f = 5+ 15 = 20              => divide both sides by 4

f = 20/4 = 5

The numbers as

f:        5

2f:     10

(f-5):  0

Thank you,

MrB

5 0
3 years ago
How to reduce 22/100 to its lowest term​
zloy xaker [14]

Answer:

11/50

Step-by-step explanation:

you talk 22 and divide it by 2 & you get 11

then you take 100 and divide it by 2 and you get 50

5 0
3 years ago
Read 2 more answers
Can someone help with this math question please
Ugo [173]
DC-10
At t=0 the altidude is 4500 feet
It's descending at a rate of 150 feet per minute, then each 5 minutes it descends (150 feet/min)(5 min)=750 feet. Then:
At t=5 the altitude is 4500 feet-750 feet=3750 feet
At t=10 the altitude is 3750 feet-750 feet=3000 feet

727
At t=0 the altidude is 600 feet
It's climbing at a rate of 75 feet per minute, then each 5 minutes it climbs (75 feet/min)(5 min)=375 feet. Then:
At t=5 the altitude is 600 feet+375 feet=975 feet
At t=10 the altitude is 975 feet+375 feet=1350 feet

The graph with these characteristics is Graph B.

Answer: The graph B shows when the two planes will be at the same altitude 
 
3 0
3 years ago
NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6. In an earlier stud
SSSSS [86.1K]

Answer:

The large sample n = 190.44≅190

The  large  sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

<u>Step-by-step explanation</u>:

Given  population proportion was estimated to be 0.3

p = 0.3

Given maximum of error E = 0.04

we know that maximum error

M.E = \frac{Z_{\alpha } \sqrt{p(1-p)} }{\sqrt{n} }

The 85% confidence level z_{\alpha } = 1.44

\sqrt{n} = \frac{Z_{\alpha } \sqrt{p(1-p)} }{m.E}

\sqrt{n} = \frac{1.44X\sqrt{0.3(1-0.3} }{0.04}

now calculation , we get

√n=13.80

now squaring on both sides n = 190.44

large sample n = 190.44≅190

<u>Conclusion</u>:-

Hence The  large  sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

7 0
3 years ago
How do you solve <br> -32+2a=0
Semmy [17]
If you're solving for a, you would add 32 to both sides
2a=32
then you would divide by 2
a=16
6 0
3 years ago
Read 2 more answers
Other questions:
  • The probability for success of an event is P(A), and the probability of success of a second event is P(B). What is the
    9·2 answers
  • How is the area of a trapezoid related to the area of a rectangle?​
    6·1 answer
  • Rob collects data about how many customers
    10·2 answers
  • What is the volume of a cylinder with the radius of 1 meter and the length of 2 meters ​
    6·1 answer
  • What best describes perpendicular rays
    10·1 answer
  • The lesson is 19.2 Angles in inscribed Quadrilaterals
    14·1 answer
  • Need help on this please
    9·1 answer
  • What does 2x-9=7x-44
    10·2 answers
  • SOMEONE PLEASE HELP! ITS ALMOST DUE!
    9·2 answers
  • PLEASE HELP WILL MARK BRAINLIEST
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!