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3 years ago

Please I need your help on this.

Mathematics

1 answer:

just olya [345]3 years ago

8 0

Answer:

the answer is 7 7/8

Step-by-step explanation:

1. you will need to change the fractions into an improper fraction.

2. you need to then multiply the numerator and denominator to get a 63/8

3. change 63/8 into a mixed fraction leaving you with 7 7/8

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Simplify the exponential problem 7b^5/b^4

Norma-Jean [14]

Solution:

If the numerator and the denominator have like bases in exponents, then the exponents subtract.

$\frac{7b^5}{b^4} = 7b^5^{-4}$
=> $7b$

Thus, 7b is the simplified expression.

5 0

2 years ago

Read 2 more answers

Helps, also explain how to do it I want to learn how and stop using brainy

Nutka1998 [239]

Answer:

259

Step-by-step explanation:

USE PEMDAS

Parenthesis

Exponent

Multiplication

Division

Addition

Subtraction

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3 years ago

Ryan made 4 identical necklaces, each having beads and a pendant. the total cost of the beads and pendants for all 4 necklaces w

Monica [59]

Write an equation to show all elements:

Cost of 4 lots of b (beads) + cost of 4p (pendants) = $18.80

Put values in;
9.29 + 4p = 18.80
4p = 18.80 - 9.20
4p = 9.60
p = 2.40 cost of each pendant

5 0

3 years ago

Mrs. Anders gave her class 15 minutes to read. Courtney read 8 ½ pages in that time. At what rate, in pages per hour, would Cour

arlik [135]

Answer:

Step-by-step explanation:

15 mins is 1/4 od an hour so mulitply 8 1/2 (8.5) x 4

4 0

3 years ago

Read 2 more answers

1. Writing an equation for an exponential function by

Naya [18.7K]

Answer: 1) $t(n)=0.6(2)^n$

2) $f(x)=10(5)^x$

Step-by-step explanation:

1) Let the function that shows the thickness of the paper after n folds,

$t(n) = ab^n$ ---------(1)

Since, According to the question,

Initially the thickness of the paper = 0.6

That is, at n = 0, t(0) = 0.6

By equation (1),

$0.6 = a(b)^0\implies 0.6 = a$

Hence the function that shows the given situation,

$t(n) = 0.6 b^n$ -----------(2)

Again when we fold the paper the thickness of the paper will be doubled.

Thus, at n = 1, t(1) = 1.2

By equation (2),

$1.2 = 0.6 b^1\implies 2 = b$

Thus, the complete function is,

$t(n) = 0.6 (2)^n$

2) Let the function that is passing through the points (-2, 2/5) and (-1,2),

$f(x) = ab^x$ ---------(1)

For f(x) = 2, x = -1

By equation (1),

$2= ab^{-1}$ ---------(2)

Also, For f(x) = 2/5, x = -2

Again, By equation (1),

$\frac{2}{5}= a(b)^{-2}$

$\implies \frac{2}{5}=ab^{-1}b^{-1}=2b^{-1}$

$\implies \frac{2}{5}=\frac{2}{b}$

$\implies 2b=10$

$\implies b = 5$

By substituting this value in equation (2),

We get, a = 10

Hence, from equation (1), the function that is passing through the points (-2, 2/5) and (-1,2),

$f(x) = 10(5)^x$

5 0

3 years ago