All categories

3 years ago

TUU SILICU.

Mathematics

2 answers:

givi [52]3 years ago

6 0

Answer:

$r = 5 , V= 105$

And for this case we want to find the height, if we solve for h from equation (1) we got:

$h = \frac{3V}{\pi r^2}$

And replacing we got:

$h = \frac{3*105}{3.14 (5)^2} = 4.01$

And then height would be given by:

$h =4.01 units$

Step-by-step explanation:

For this case we know that the volume for a cone is given by this formula:

$V = \frac{\pi r^2 h}{3}$ (1)

And from the info given we have:

$r = 5 , V= 105$

And for this case we want to find the height, if we solve for h from equation (1) we got:

$h = \frac{3V}{\pi r^2}$

And replacing we got:

$h = \frac{3*105}{3.14 (5)^2} = 4.01$

And then height would be given by:

$h =4.01 units$

Shalnov [3]3 years ago

4 0

Answer:

4.013 units

Step-by-step explanation:

We know that the volume of a cone is given by the following equation:

v = pi / 3 * r ^ 2 * h

we need to know the height, therefore we solve for h:

h = 3 * v / (pi * r ^ 2)

replacing v = 105 and r = 5

h = 3 * 105 / (3.14 * 5 ^ 2)

h = 4.013

Which means that the height measures 4.013 units

You might be interested in

Kyle is practicing for a 3-mile race. His normal time is 23 minutes 25 seconds. Yesterday it took him only 21 minutes 38 seconds

diamong [38]

Answer:2:24

Step-by-step explanation:

7 0

3 years ago

2. Which of the following shows the correct area of the figure below rounded to the nearest hundredths place.

Lera25 [3.4K]

Answer:

the answer is 190.07 cm2

8 0

2 years ago

Describe in words the translation represented by the translation rule (x, y) The image is a right pointing arrow. (x – 7, y – 7)

Vesna [10]

A, tell me if wrong. Also if it it wrong i am really sorry

5 0

2 years ago

Read 2 more answers

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :

For the first parenthesis:

$x^{2}+6x+b^{2}$

We can rewrite this as:

$x^{2}+2(3)x+b^{2}$

Hence in this case $b=3$ and $b^{2}=9$ :

$x^{2}+2(3)x+3^{2}=x^{2}+6x+9=(x+3)^{2}$

For the second parenthesis:

$y^{2}-8y+b^{2}$

We can rewrite this as:

$y^{2}-2(4)y+b^{2}$

Hence in this case $b=-3$ and $b^{2}=9$ :

$y^{2}-2(4)y+4^{2}=y^{2}-8y+16=(y-4)^{2}$

Then, equation (5) is rewritten as follows:

$(x^{2}+6x+9)+(y^{2}-8y+16)=75+9+16$ (6)

Note we are adding 9 and 16 in both sides of the equation in order to keep the equality.

Rearranging:

$(x-3)^{2}+(y-4)^{2}=100$ (7)

At this point we have the circle equation in the center radius form $(x-h)^{2} +(y-k)^{2}=r^{2}$

Hence:

$h=-3$

$k=4$

$r=\sqrt{100}=10$

8 0

3 years ago

A triangle ABC is inscribed in a circle, such that AB is a diameter. What are the measures of angles of this triangle if measure

Katen [24]

Answer:

∠C=90°

∠A=67°

∠B=23°

Step-by-step explanation:

For angle C:

Thales' Theorem states that an angle inscribed across a circle's diameter is always a right angle.

Therefore, since AB is the diameter(hypotenuse) then angle C is the right angle. (90°)

For Angle A:

The measure of arc BC= 134 degrees. We can just use a formula for an inscribed triangle. ∠A = 1/2 (mBC)

∠A= (1/2)134

∠A= 77°

For angle B:

All triangle angles all add up to 180. We can just subtract angles A and C from 180°:

∠B = 180-(90+67)

∠B = 23°

8 0

3 years ago