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Masja [62]
3 years ago
13

Draw a circle.Show at least 4 different lines of symmetry​

Mathematics
2 answers:
GREYUIT [131]3 years ago
7 0
Explanation:
Hope this is helpful




EleoNora [17]3 years ago
6 0

Hope this helps! Have a nice day or night!

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What is the max value of 18.6
Free_Kalibri [48]
The answer would be 19.0
7 0
3 years ago
Missing side length
Gwar [14]

Answer:

m = 5

Step-by-step explanation:

We are told that the two triangles are similar.  Thus, each side of the larger triangle is the same multiple of the corresponding side in the smaller triangle.

Thus, 12 = k(7.2), where k is the constant of proportionality.

Solving this for k, we get

k = 12/7.2 = 1  2/3

Thus, side m is 1  2/3 times 3, or  5/3 times 3, or just 5.

m = 5

8 0
4 years ago
Tanner has the following data:
Sever21 [200]

Answer:

74

Step-by-step explanation:

74+73+71+73+73+74=438÷6=73

5 0
2 years ago
Hi! I've tried this problem a couple times but am still stumped :( Can you help?!
aniked [119]

ANSWER:

X\text{ = }\begin{bmatrix}{12} & {-4} & {-2} \\ {-8} & {-13} & {8} \\ {8} & {15} & {18}\end{bmatrix}

EXPLANATION:

Given:

U\text{ = }\begin{bmatrix}{1} & {3} & {-5} \\ {2} & {14} & {11} \\ {-8} & {0} & {5}\end{bmatrix}\text{           V =}\begin{bmatrix}{13} & {1} & {-7} \\ {-6} & {1} & {9} \\ {0} & {15} & {23}\end{bmatrix}

Since U and V are Matrices with equal dimensions(3 x 3 matrix), and

X + U = V.

To solve for X, we have:

X = V - U

\begin{gathered} X\text{ = V - U} \\ X\text{ = }\begin{bmatrix}{13-1} & {-1-3} & {-7-(-5)} \\ {-6-2} & {1-14} & {19-11} \\ {0-(-8)} & {15-0} & {23-5}\end{bmatrix}=\text{ }\begin{bmatrix}{12} & {-4} & {-2} \\ {-8} & {-13} & {8} \\ {8} & {15} & {18}\end{bmatrix} \end{gathered}X\text{ = }\begin{bmatrix}{12} & {-4} & {-2} \\ {-8} & {-13} & {8} \\ {8} & {15} & {18}\end{bmatrix}

6 0
1 year ago
Log16^*+log4^*+log2^*=7​
ale4655 [162]

Answer:

x = 16

Step-by-step explanation:

Given

log_{16}(x) + log_4(x) + log_2(x) = 7

Required

Solve for x

log_{16}(x) + log_4(x) + log_2(x) = 7

Change base of 16 and base of 4 to base 2

\frac{log_2(x)}{log_2(16)} + \frac{log_2(x)}{log_2(4)} + log_2(x) = 7

Express 16 and 4 as 2^4 and 2^2 respectively

\frac{log_2(x)}{log_2(2^4)} + \frac{log_2(x)}{log_2(2^2)} + log_2(x) = 7

The above can be rewritten as:

\frac{log_2(x)}{4log_22} + \frac{log_2(x)}{2log_22} + log_2(x) = 7

log_22 = 1

So, we have:

\frac{log_2(x)}{4*1} + \frac{log_2(x)}{2*1} + log_2(x) = 7

\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x) = 7

Multiply through by 4

4(\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x)) = 7 * 4

log_2(x) + 2}log_2(x) + 4log_2(x) = 28

7log_2(x) = 28

Divide through by 7

\frac{7log_2(x)}{7} = \frac{28}{7}

log_2(x) = 4

Apply the following law of logarithm:

<em>If </em>log_ab = c<em> </em><em>Then </em>b = a^c<em></em>

So, we have:

x = 2^4

x = 16

6 0
3 years ago
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