Answer:
p = 0.36
q = 0.64
p² = 0.13
2pq = 0.46
q² = 0.41
Explanation:
We need to use the Hardy-Weinberg equations:
p + q = 1
p² + 2pq + q² = 1
p: the frequency of the dominant allele
q: the frequency of the recessive allele
p²: the frequency of homozygous dominant
2pq: the frequency of heterozygous
q²: the frequency of homozygous recessive
Here, we know that 328/800 people are homozygous recessive, which means that q² = 328/800 = 0.41.
Then, q = √0.41 = 0.64, and p = 1 - q = 1 - 0.64 = 0.36.
Now, we have p² = (0.36)² = 0.1296 ≈ 0.13 and 2pq = 2 * 0.36 * 0.64 = 0.4608 ≈ 0.46.
The answers are:
p = 0.36
q = 0.64
p² = 0.13
2pq = 0.46
q² = 0.41
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The nurse should try to find an oximetry sensor that is not so tight so that the baby will not feel discomfort and thus respond in that way to the caregiver's concerns and alleviate the problem by taking these appropriate measures.
The bell shaped curve indicates polygenic traits. A polygenic trait is controlled by multiple alleles. Hope this makes sense :)