What are the vertices of the hyperbola whose equation is (x+3)^2/4 - (y-5)^2/16 =1
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Answer
1/2+2×(sqrt3)^2+x.(sqrt3/2)^2=8+1^2+1/2
1/2+2×3+x.3/4=8+1+1/2
1/2-1/2+6+x.3/4=9
x.3/4=9-6
x.3×4=3
x.3=3×4
x.3=12
x=12/3
x=4.
so, the value of x is 4.
hope it helps you.
