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Romashka-Z-Leto [24]
3 years ago
15

What are the vertices of the hyperbola whose equation is (x+3)^2/4 - (y-5)^2/16 =1

Mathematics
1 answer:
Marina CMI [18]3 years ago
7 0

Answer:B

Step-by-step explanation:

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Write an equation in standard form for the line that had an undefined slope and passed through (-6, 4)
guajiro [1.7K]

x = -6 is the equation for this question.


5 0
3 years ago
Please help asap!! Thank you
djyliett [7]

Step-by-step explanation:

Hey, there!!

Let's simply work with it,

60° + 2x° + (2x+12)° = 180° { being a linear pair}.

or, 72° + 4x = 180°

4x = 180° - 70°

x =  \frac{108}{4}

Therefore, the value of x is 27°.

Now,

2x° = (2×27)°= 54°

(2x+12)° = 2×27°+12°= 66°.

(x+2)= 27+ 2= 29°

Now, The left angle is 27°.

Therefore, The answer is option A.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

6 0
3 years ago
HELP PLEASE HELP HELP
kupik [55]
I think it’s 0but not s
5 0
2 years ago
Simplify the rational expression. State any restrictions on the variable. t^2-4t-32/t-8
Leno4ka [110]

1. Factor the expression t^2-4t-32:

t^2-4t-32=(t-8)(t+4).

2. Since t-8 is placed in the denominator of the given expression, then t\neq 8.

3. Now the expression can be simplified:

\dfrac{t^2-4t-32}{t-8}=\dfrac{(t-8)(t+4)}{t-8}=t+4.

5 0
3 years ago
Read 2 more answers
-2 (m+n-4)+5 (-2m+2n)+n (m+4n-5)
Natalka [10]
So if you want to add
we distribute
a(b+c)=ab+ac so
-2(m+n-4)=-2m-2n+8

5(-2m+2n)=-10m+10n

n(m+4n-5)=mn+4n^2-5n

so total we ahve
-2m-2n+8-10m+10n+mn+4n^2-5n
group like terms
4n^2+-2m-10m-2n+10n-5n+mn+8
add like temrs
4n^2-12m+3n+mn+8
5 0
3 years ago
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