An alternating series
converges if
is monotonic and
as
. Here
.
Let
. Then
, which is positive for all
, so
is monotonically increasing for
. This would mean
must be a monotonically decreasing sequence over the same interval, and so must
.
Because
is monotonically increasing, but will still always be positive, it follows that
as
.
So,
converges.
I am setting the week hourly rate to x, and the weekend to y. Here is how the equation is set up:
13x + 14y = $250.90
15x + 8y = $204.70
This is a system of equations, and we can solve it by multiplying the top equation by 4, and the bottom equation by -7. Now it equals:
52x + 56y = $1003.60
-105x - 56y = -$1432.90
Now we add these two equations together to get:
-53x = -$429.30 --> 53x = $429.30 --> (divide both sides by 53) x = 8.10. This is how much she makes per hour on a week day.
Now we can plug in our answer for x to find y. I am going to use the first equation, but you could use either.
$105.30 + 14y = $250.90. Subtract $105.30 from both sides --> 14y = $145.60 divide by 14 --> y = $10.40
Now we know that she makes $8.10 per hour on the week days, and $10.40 per hour on the weekends. Subtracting 8.1 from 10.4, we figure out that she makes $2.30 more per hour on the weekends than week days.
Answer:
0% probability that a customer will be exactly 7.50 minutes in the record store.
Step-by-step explanation:
Uniform probability distribution:
An uniform distribution has two bounds, a and b.
The probability of finding a value of at lower than x is:
The probability of finding a value between c and d is:
The probability of finding a value above x is:
The uniform distribution is a continuous distribution, which means that the probability of an exact outcome is zero.
Uniformly distributed between 3 and 12 minutes.
This means that 
What is the probability that a customer will be exactly 7.50 minutes in the record store?
Continuous distribution, so:
0% probability that a customer will be exactly 7.50 minutes in the record store.
Answer:
Step-by-step explanation:
Hope it helps!
It depends on what the graph shows. I need to see the graph to help you. sorry
