(a + 1)(a² + 2a + 1)
= a(a² + 2a + 1) + 1(a² + 2a + 1)
= a³ + 2a² + a + a² + 2a + 1
= a³ + 3a² + 3a + 1
Answer: b
9514 1404 393
Answer:
x ≠ 3
Step-by-step explanation:
In any case, the domain is restricted to values of the variable for which the function is defined. The value 1/0 is not defined, so the variable cannot allow the denominator to be zero. The denominator x-3 will be zero for x=3, so that value of the variable cannot be in the domain.
The domain is all real numbers except x=3.
_____
<em>Additional comments</em>
It is useful to become familiar with the domains of different functions. As we saw above, the reciprocal of 0 is undefined. The square root of a negative number is undefined. The log of a non-positive number is undefined. Trig functions are defined everywhere, but their inverse functions are not. Polynomial functions are defined everywhere, but ratios of polynomials have the same restriction on denominators that we see above.
No nodcause it has to me in y=mx+b form. so just sub. 1 from each side
Answer:
Step-by-step explanation:
So let's think about what values you can take square root of...
anything but negative values!
So the first one is not correct because you can also take square root of 0,
squareroot of 0 is 0.
So because of this, C and D are both correct, E is correct because root x is an increasing function. B is incorrect because (0,0) is an intercept.
