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6 0

2 years ago

Read 2 more answers

Point A is at (6,-6) and point C is at(-6,-2). find the coordinates of B on AC so that AB= 3/4AC.

loris [4]

Answer:

B(-6, 0)

Step-by-step explanation:

You want to find B such that ...

(B -A) = (3/4)(C -A) . . . . the required distance relation

4(B -A) = 3(C -A) . . . . . . multiply by 4

4B = 3C +A . . . . . . . . . . add 4A, simplify

Now, we can solve for B and substitute the given coordinates:

B = (3C +A)/4 = (3(-6, -2) +(-6, 6))/4 = (-24, 0)/4 = (-6, 0)

The coordinates of point B are (-6, 0).

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

6 0

2 years ago

Find functions f and g such that h = g ∘ f. (note: the answer is not unique. enter your answers as a comma-separated list of fun

polet [3.4K]

It is given in the question that

$h(x) = (fog)(x) = x^2 -81$

And $x^2 -81$

can also be written as

$(x^2 -40) -41$

Therefore,

$(fog)(x) = (x^2 -40)-41$

$f(g(x)) = (x^2 -40)-41$

That gives,

$g(x) = x^2 -40, f(x) = x-41$

7 0

2 years ago