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Colt1911 [192]
3 years ago
13

old stars obtain part of their energy by the fusion of three alpha particles to form a 12/6c nucleus, whose mass is 12.0000 u. H

ow much energy is given off in each such reaction?
Physics
1 answer:
marta [7]3 years ago
7 0

Answer:

11.6532 x 10⁻¹¹ J or 7.3 MeV is given off

Explanation:

Mass of an alpha particle = 4.0026u,   ∴ mass of three = 12.0078u

Find the difference in mass.

Mass of three alpha - Mass of Carbon nucleus

12.0078u - 12u = 0.0078u

Since 1u = 1.66 x 10⁻²⁷ kg

Therefore, 0.0078u = 1.2948 x 10⁻²⁷

Now that we know Mass(m) = 1.2948 x 10⁻²⁷ and Speed (c) 3 x 10⁸ m²s⁻²

Formular for Energy ==> E₀ = mc²

E = (1.2948 x 10⁻²⁷) (3 x 10⁸ m²s⁻²)²

E = (1.2948 x 10⁻²⁷) (9 x 10¹⁶) J

E = 11.6532 x 10⁻¹¹ J

Or, if you need your energy in MeV

1 MeV = 1.60x10⁻¹³ J

Just do the conversion by dividing 11.6532 x 10⁻¹¹ J by 1.60x10⁻¹³ J

It will give you 7.3 MeV

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If an object has a mass of 1417g and it is moved 47 meters in 90 seconds, how much power was used?
astraxan [27]

Mass of the object is given as

m = 1417 g = 1.417 kg

now the speed of object is given as

v = \frac{d}{t}

here we know that

d = 47 m

t = 90 s

now we will have

v = \frac{47}{90} = 0.52 m/s

now we will have kinetic energy of the object as

KE = \frac{1}{2}mv^2

KE = \frac{1}{2}(1.417)(0.52)^2

KE = 0.19 J

now the power is defined as rate of energy

so here we can find power as

P = \frac{KE}{t}

P = \frac{0.19}{90} = 2.14\times 10^{-3} W

so above is the power used for the object

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4 years ago
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andrey2020 [161]
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6 0
3 years ago
Read 2 more answers
What is a key difference between cell signaling by a cell-surface receptor and cell signaling by an intracellular receptor?
Art [367]

CORRECT ANSWER:

a- Cell-surface receptors bind polar signaling molecules; intracellular receptors bind nonpolar signaling molecules.

STEP-BY-STEP EXPLANATION:

The complete question from book is

According to Figure 9.6, what is a key difference between cell signaling by a cell-surface receptor and cell signaling by an intracellular receptor?

a- Cell-surface receptors bind polar signaling molecules; intracellular receptors bind nonpolar signaling molecules.

b- Signaling molecules that bind to cell-surface receptors lead to cellular responses restricted to the cytoplasm; signaling molecules that bind to intracellular receptors lead to cellular responses restricted to the nucleus.

c- Cell-surface receptors bind to specific signaling molecules; intracellular receptors bind any signaling molecule.

d- Cell-surface receptors typically bind to signaling molecules that are smaller than those bound by intracellular receptors.

e- None of the other answer options is correct.

3 0
4 years ago
A hanging wire made of an alloy of titanium with diameter 0.05 cm is initially 2.7 m long. When a 15 kg mass is hung from it, th
Svet_ta [14]

Answer:

Explanation:

Young's modulus of elasticity Y = stress / strain

stress = force / cross sectional area

= weight of 15 kg / π r²

= 15 x 9.8 / 3.14 x ( .025 x 10⁻² )²

stress = 74.9 x 10⁷ N / m²

strain = Δ L / L , Δ L is change in length and L is original length

Putting the values

strain = .0168 / 2.7 =.006222

Young's modulus of elasticity Y  = 74.9 x 10⁷ / .006222

= 120.88 x 10⁹ N / m² .

8 0
3 years ago
At 13:20 on the last Friday in September, 1989 a frantic call was received at the local police station. There had been a serious
astraxan [27]

The kinematics and conservation of momentum relationships allow to find the results for the questions about the measurements and conditions to know the accident conditions are:

     1) The principles of conservation of momentum  and kinematics.

     2)  \theta = tan^{-1} \frac{P_{01}}{p_{02}}

     3) The factors that influence the direction and distance traveled are:

         The initial speed of the vehicles

         The mass of the vehicles

         Pavement conditions: dry, wet, humid, with dirt or loose sand.

1) Kinematics studies the movement of bodies, they look for relationships between position, speed and acceleration.

To analyze the accident, you must answer a question such as what speed the vehicles had before the accident, this is the initial speed of each one and their directions.

When reviewing the kinematics relationships we have.

        v^2 = v_o^2 - 2 a x  

Where the acceleration is given by Newton's second law.

        fr = m a

The friction force is given by the expression.

       fr = μ N  

       fr = μ mg

       

Let's Substitute.

         μ m g = m a

         a = μ g

The friction coefficient is tabulated, for different types of rubber, pavement and wet,  dry conditions, etc.

Therefore, the researcher must measure the braking distance of the vehicles, which can be taken from the mark of the tires on the road and note the condition of the pavement if it is dry or wet and the visibility of the day.

This is the speed of the vehicles just after the impact, using the law of conservation of momentum you can find the speed of the vehicles before the impact

        p_o = p_f \f

         

Where this is a vector expression, which in general is solved with the components of each directional.

Consequently to answer the questions you must use the principles of conservation of momentum  and kinematics.

2) If the vehicles travel at right angles and their masses are similar, the direction after the collision  in each direction.

           tan \theta = \frac{p_{01}}{p_{02}}  

           \theta = tan ^{-1} \frac{p_{01}}{p_{02}}  

3) The factors that influence the direction and distance traveled are:

     The initial speed of the vehicles

     The mass of the vehicles

     Pavement conditions: dry, wet, humid, with dirt or loose sand.

In conclusion, using the kinematics and conservation of momentum relationships, we can find the answers to the question about measurements and conditions to know the accident conditions are:

      1) The principles of conservation of momentum  and kinematics.

     2)  \theta = tan^{-1} \frac{P_{01}}{p_{02}}

     3) The factors that influence the direction and distance traveled are:

         The initial speed of the vehicles

         The mass of the vehicles

         Pavement conditions: dry, wet, humid, with dirt or loose sand.

Learn more about kinematics and momentum here:   brainly.com/question/17304001

5 0
3 years ago
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