Answer:
three consecutive odd integers: 2n-1 2n+1 2n+3
that the sum of the smaller two is three
times larger increased by seven: 2n-1 + 2n+1 = 3(2n+3) +7
4n = 6n+ 9 +7
4n = 6n+ 16
4n -6n = 16
-2n = 16
n = 16/(-2)
n=-8
a) 2n -1 = 2(-8) -1 = -17
b) 2n+1 = 2(-8)+1 = -15
c) 2n+1 = 2(-8)+3 = -13
Ans. -17 ; -15 ; -13
Answer:
-2
Step-by-step explanation:
12=2+7d
7d= -12-2
7d= -14
d= -14
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7
d= -2
Answer:
what is your question
Step-by-step explanation:
A standard algorithm is a step-by-step way to solve a problem.
In plain and short, what's 2/3 of 7/8? well, is just their product.
