Answer:
-3 is the value of the location where the line crosses the y-axis,and is commonly referred in the slope-intercept form of a line "the intercept". Now it may be your teacher expects you to answer this as the point on the plane where the y-intercept occurs, and that should be the point (0, -3). Make sure you follow your teacher's notation.
Step-by-step explanation:
Re-write the equation given in slope=intercept form by isolating the variable "y" on one side of the equation and expressing the rest in slope*x + y-intercet form:

which tells us that the slope of the line is -2 and it y-intercept is "-3".
Now, watch out because you may be asked to write the actual coordinates of the y-intercept, which are: (0, -3)
giving the x-coordinate 0 and the y-value where the line crosses the y-axis.
if it has a diameter of 8, that means its radius is half that, or 4.
![\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=4\\ h=5 \end{cases}\implies V=\cfrac{\pi (4)^2(5)}{3}\implies V=\cfrac{80\pi }{3} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{using~\pi =3.14}{V= 83.7\overline{3}}~\hfill](https://tex.z-dn.net/?f=%20%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%0AV%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D~~%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Ar%3D4%5C%5C%0Ah%3D5%0A%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20%284%29%5E2%285%29%7D%7B3%7D%5Cimplies%20V%3D%5Ccfrac%7B80%5Cpi%20%7D%7B3%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A~%5Chfill%20%5Cstackrel%7Busing~%5Cpi%20%3D3.14%7D%7BV%3D%2083.7%5Coverline%7B3%7D%7D~%5Chfill%20)
Your answer is 25% <span> of change in the price of a radio</span>
Answer:
Given :
→x-y=12
→xy= 3²
=9
Equation formed:

Step by step explanation:

hope it helped you:)
Answer:
corresponding
Step-by-step explanation:
because they are in the same place on both intersections. now if u ask me doggo deserve breinliest pwease ;-;