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Margaret [11]
3 years ago
11

What is the square root of 16?

Mathematics
1 answer:
salantis [7]3 years ago
8 0

Answer: 4

Step-by-step explanation:

the square root of 16 is what you square to get 16

4 * 4 = 16

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73. you subtract 89 and 16 and that gives you your answer which is*** 73***
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Express 0.1111111...+0.01010101010101....+ 0.000100010001 as a common fraction.
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Sent a picture of the solution to the problem (s).

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Help me pls! I have to get his done.<br>Factorise this!<br>2x^2+5x+3​
MArishka [77]

Hello there!☺

Answer:\boxed{(2x+3)(x+1)}

Explanation:

2x^2+5x+3 Factorized

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4 years ago
Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer
Mumz [18]

Answer:

C) Both

Step-by-step explanation:

The given equation is:

0=(3x+2)(x-4)

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.

Using this property:

(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply (3x+2)(x-4) i.e. 3x^2-12x+2x-8 = 3x^2-10x-8

So, the equation becomes:

0=3x^2-10x-8

Comparing this equation to standard quadratic equation:

ax^2+bx+c=0

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}

The answer is same from both the approaches.

So, the correct answer is:

C) Both

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