The distance travelled by an object at time t is given by: d = stwhere d is the distance, s is the speed and t is the time.
Given that the cheetah travels a maximum of 70mph, the distance travelled by the cheetah travelling at 70mph at time t is given by d = 70t
There are 60 mins in one hour, so the distance given in miles per minutes is d = 70/60t = 1.167 miles per minutes.
Part B:
Given that t = 10 minutes, the distance covered by the cheetah in 10 minutes is d = 1.167 x 10 = 11.67 miles.
Part C:
If the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes, then the number of minutes the cheetah have traveled in the first 8 minutes is given by
d = 1.167 x 8 = 9.33 miles.
Part D:
If the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes, then the number of minutes the cheetah have traveled in the second 8 minutes is given by
d = 40/60 x 8 = 5.33 miles
Part E:
The distance the cheetah traveled in the first 8 minutes more than in the second 8 minutes is given by
9.33 miles - 5.33 miles = 4 miles.
Part F:
The ratio of the distance travelled in the first 8 minutes to the distance travelled in the next minutes is given by
9.33 : 5.33 = 1.75 : 1.
Therefore, the distance traveled by the cheetah during the first 8 minutes is 1.75 times greater than the distance traveled during the second 8 minutes.
Answer:
The graph in the attached figure
Step-by-step explanation:
we know that
The equation of a circle into center radius form is equal to
![(x-h)^{2}+(y-k)^{2}=r^{2}](https://tex.z-dn.net/?f=%28x-h%29%5E%7B2%7D%2B%28y-k%29%5E%7B2%7D%3Dr%5E%7B2%7D)
where
(h,k) is the center of the circle
r is the radius of the circle
In this problem we have
![(x)^{2}+(y-4)^{2}=2.25](https://tex.z-dn.net/?f=%28x%29%5E%7B2%7D%2B%28y-4%29%5E%7B2%7D%3D2.25)
therefore
the center is the point ![(0,4)](https://tex.z-dn.net/?f=%280%2C4%29)
the radius is ![\sqrt{2.25}=1.5\ units](https://tex.z-dn.net/?f=%5Csqrt%7B2.25%7D%3D1.5%5C%20units)
using a graphing tool
see the attached figure
3b+2(b-1) = 8
3b+2b-2 = 8
5b = 8+2
5b = 10
b = 2