Answer:
one solution.............
The answer is m = 250 - 25w.
This is because this answer is in y=mx+b format (slope-intercept form) and has the correct values.
In slope-intercept form, m is the slope and b is y-intercept.
In m = 250 - 25w, the y-intercept is 250 and the slope is -25.
This matches the graph.
Y-intercept is where a line crosses the y-axis, which is 250 in this case.
The slope is negative since the values are decreasing over time (as x-values increase, y-values decrease).
Answer:10x
Step-by-step explanation:
yes
Answer:
its the second one
The relationship between independent variable A and dependent variable C, and the relationship between independent variable B and dependent variable C can both be analyzed, but they must be analyzed using separate scatterplots.
Step-by-step explanation:
Answer:
0.7486 = 74.86% probability of family expenses for the weekend being more than $580.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The American Automobile Association reported that families planning to travel over the Labor Day weekend would spend an average of $735.
This means that 
Assume that the amount spent is normally distributed with a standard deviation of $230.
This means that 
What is the probability of family expenses for the weekend being: a. more than $580
This is 1 subtracted by the pvalue of Z when X = 580. So



has a pvalue of 0.2514
1 - 0.2514 = 0.7486
0.7486 = 74.86% probability of family expenses for the weekend being more than $580.