Answer:
Yes, she can drew a right triangle with these sides
Step-by-step explanation:
To answer this question we first have to prove the Pythagorean theorem
h = hyoptenuse
a = leg 1
b = leg2
h² = a² + b²
We have to replace the values that they gave us in this formula
The hypotenuse always has to be the longest side of a right triangle
(14cm)² = (11.2cm)² + (8.4cm)²
196cm² = 125.44cm² + 70.56cm²
196cm² = 196cm²
As we can see, equality is fulfilled, so she is correct
If you're supposed to find the measure of the arc:
The minor arc CD has the same measure as the central angle it subtends. In this case, arc CD has measure 50º. In radians, that's
50º * (π/180 rad/º) = 5π/18 rad
If you instead meant to ask about finding the length of the arc CD, recall that arc lengths and their subtended central angles occur in a fixed ratio equal to the ratio of the circle's total circumference to 2π rad. In other words, if <em>L</em> is the length of the minor arc CD, then
<em>L</em> /(5π/18 rad) = 2π (7 cm) / (2π rad)
==> <em>L</em> = 35π/18 cm
(Notice that arc measure is given radians, while arc length is given in cm, which is why I offer two different answers here.)
Answer:
Step-by-step explanation:
Proportion of retired people under the age of 65 would return to work on a full-time basis if a suitable job were available = 60/100 = 0.6 = P
Null hypothesis: P ≤ 0.6
Alternative: P > 0.6
First, to calculate the hypothesis test, lets workout the standard deviation
SD = √[ P x ( 1 - P ) / n ]
where P = 0.6, 1 - P = 0.4, n = 500
SD = √[ (0.6 x 0.4) / 500]
SD = √ (0.24 / 500)
SD = √0.00048
SD = 0.022
To calculate for the test statistic, we have:
z = (p - P) / σ where p = 315/500 = 0.63, P = 0.6, σ = 0.022
z = (0.63 - 0.6) / 0.022
z = 0.03/0.022
z = 1.36
At the 2% level of significance, the p value is less than 98% confidence level, thus we reject the null hypothesis and conclude that more than 60% would return to work.
Answer:
<h3>The place value of 6 in the number 346 094 is Thousand.</h3>
Step-by-step explanation:
<h3>I hope it helps ❤❤</h3>