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lutik1710 [3]
3 years ago
7

(6x + 7) - (9x + 9) simpilest form pls

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
8 0

Answer:

-3x-2

Step-by-step explanation:

My name is Ann [436]3 years ago
7 0

Answer:

-3x+16

Step-by-step explanation:

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What trig function would I use to solve for x?
IRINA_888 [86]

Answer:

Cosine

Step-by-step explanation:

SohCahToa

The sides are: adjacent to the angle and are the hypotenuse.

(hope this helps :P)

8 0
2 years ago
Find x step by step (10 points)
AleksandrR [38]

Answer:

\sqrt{(n-m)(n+m)} & -\sqrt{(n-m)(n+m)}

Step-by-step explanation:

1) Subtract m^{2} from both sides. This should leave you with x^{2}=n^{2}-m^{2}.

2) Square root both sides. This should leave you with x=\sqrt{n^2-m^2} & x=-\sqrt{n^2-m^2}.

<em>You can stop here if this is what the problem is asking for. However, it is not fully simplified.</em>

<em />

3) Factor the equation. This should leave you with \sqrt{(n-m)(n+m)} & -\sqrt{(n-m)(n+m)}.

4 0
2 years ago
Read 2 more answers
What is the solution to the system x+y=10 3y=-3x+30<br><br> PLEASE helpppp
choli [55]

Answer:

Step-by-step explanation:

x+y=10

x=10-y

x=10-5

x=5

3y= -3x+30

3(10-y)= -3(10-y)+30

30-3y= -30+3y+30

30+30-30=6y

30=6y

y=5

6 0
3 years ago
Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than
Fittoniya [83]
Inequation 1: 

\frac{2}{3}x-3 \geq y

to plot the pairs (x, y) for which the inequation holds, draw the line y=\frac{2}{3}x-3

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2: 

y+ \frac{2}{3}x\ \textless \ 4

y\ \textless \ - \frac{2}{3} x+ 4&#10;


draw the lines 

i)  y=\frac{2}{3}x-3          use points (0, -3),  (3, -1)

ii)y=- \frac{2}{3} x+ 4       use points ( 0, 4),   (3, 2)


let's use the point P(3, 3) to see what region of the lines need to be coloured:

\frac{2}{3}x-3 \geq y  ; 
\frac{2}{3}(3)-3 \geq 3
2-3 \geq 3, not true so we color the region not containing this point


y+ \frac{2}{3}x\ \textless \ 4
(3)+ \frac{2}{3}(3)\ \textless \ 4
3+ 5\ \textless \ 4 not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.



4 0
3 years ago
consider the line y=2/3x-0 find the equation of the line that is parallel to this line and passes through the point(8, 4).
Mila [183]
To find the equation take the slope 2/3 y-y(1)=m(x-x(1) y-4=2/3(x-8) = 2/3x-16/3 Next solve for y y=2/3x-16/3 +4(turn 4 into a fraction with a common denominator) y=2/3x-16/3 + 12/3 y=2/3x-4/3
4 0
3 years ago
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