Answer:69
Step-by-step explanation:
Her
Answer:
Problem 23) 
Problem 24) 
Step-by-step explanation:
step 1
Find the slope of the given line
The formula to calculate the slope between two points is equal to

we have

Substitute the values


step 2
Problem 23
we know that
If two lines are perpendicular then the product of its slopes is equal to minus 1
so

Find the slope of the line
we have

substitute in the equation and solve for m2


with the slope m2 and the point
find the equation of the line
Remember that
The equation of the line in slope intercept form is equal to

we have

-----> the given point is the y-intercept
substitute

step 3
Problem 24
we know that
If two lines are parallel, then its slopes are the same
so
with the slope m1 and the point
find the equation of the line
The equation of the line in slope intercept form is equal to

we have

-----> the given point is the y-intercept
substitute

Answer:
Theatre C.
Step-by-step explanation:
Theatre A:
60 of the 80 seats are taken.
% seats taken = seats taken/total seats * 100
= 60/80 * 100
= 75%
Theatre B:
Total seats = number of seats taken + number of empty seats
= 42 + 18
= 60
% seats taken = seats taken/total seats * 100
= 42/60 * 100
= 70%
Theatre C:
Total seats = number of seats taken + number of empty seats
90 = X + 18
X = 72
% seats taken = seats taken/total seats * 100
= 72/90 * 100
= 80%
Theatre C with 80% of seats taken.
Based on the information represented by the boxplot ;
- Latasha's lowest sale amount = 50
- Kayla's median is between 200 and 300
- Latasha has a greater spread due to higher IQR value
1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>
- The minimum value is denoted by the starting position of the lower whisker on a boxplot.
- Lowest amount of sale made by Latasha = 50
2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>
- 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.
- 50% of sales made by Kayla is between 200 and 300
- With median sale value being 250
3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>
- The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution
- IQR = Upper Quartile (Q3) - Lower quartile(Q1)
<u>For Latasha</u> :
- Q3 = 450 (Endpoint of the box)
- Q1 = 150 (starting point of the box)
<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>
- Q3 = 375 (Endpoint of the box)
- Q1 = 100 (starting point of the box)
- IQR = 375 - 100 = 275
- Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.
Learn more :brainly.com/question/24582786
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