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3 years ago

PLZ NEED IT RIGHT NOW!!!

Mathematics

1 answer:

Nikolay [14]3 years ago

8 0

Answer:

D. (-1, 4) sry if wrong hope it helps

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1/2 to the power of 5 equals

svp [43]

Answer:

1/32

Step-by-step explanation:

This could be written as $1/2^5\\$

1/2 x 1/2 x 1/2 x 1/2 x 1/2

= 1/32, or 0.03125.

3 0

3 years ago

Can someone plz help me

earnstyle [38]

Answer:

X=37.6 because the 90 degree angle plus the 52.4 equals 142.4 the subtract that from 180 then ta da.

6 0

3 years ago

Angela drew 9 rhombuses and 6 trapezoids. She wants to find q, the total number of angles in her quadrilaterals. Explain how Ang

Reil [10]

Both rhombuses and trapezoids have 4 angles. Angela can add 9 and 6 which will give her 15 and multiply by 4 which will give her 60.

Angela has 60 angles.

I hope this helped!!! :)

5 0

3 years ago

Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a

Alina [70]

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-620=\dfrac{749-620}{70-30}(x-30)$

$y-620=\dfrac{129}{40}(x-30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}$

Adding 620 on both sides, we get

$y=\dfrac{129}{40}x-\dfrac{387}{4}+620$

$y=\dfrac{129}{40}x+\dfrac{2480-387}{4}$

$y=\dfrac{129}{40}x+\dfrac{2093}{4}$

We need to find the y-value for $x=57$ .

$y=\dfrac{129}{40}(57)+\dfrac{2093}{4}$

$y=183.825+523.25$

$y=707.075$

$y\approx 707.1$

Therefore, the required linear equation for the given situation is $y=\dfrac{129}{40}x+\dfrac{2093}{4}$ and the average score for persons taking a 57-hour review course is 707.1.

4 0

2 years ago

The figures are similar. Find the missing length.

saw5 [17]

Step-by-step explanation:

<h2>Answer:-</h2><h3>Given ,</h3>

The figure is Similar.

Observation:-

Similar figures have similar sides. If we see carefully in smaller triangle, 3 has been added to each side and they are similar. We need to find y.

We have :-

5+3=8 as similar sides.

So, applying same algorithm,

$y + 3 = 5$

$y = 5 - 3$

$\boxed{ \tt{y = 2 \ cm}}$

is the answer.

Hope it helps :)

4 0

3 years ago