The ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
<u>Explanation:</u>
We need to find the time at which the ball will be at height 19 feet.
Equation:
h = 3 + 34t - 16t²
19 = 3 + 34t - 16t²
16 = -16t² + 34t
-16t² + 34t - 16 = 0
On solving the equation, we get
t1 = 0.7 s and t2 = 1.42s
Therefore, the ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
The answer is C.
4x-y=-8
-y=-4x-8
y=4x+8
y=4x+8
0=4x+8
-8=4x
-2=x
Answer:
Step-by-step explanation:
hello :
12x^3-9x²-4x+3= 3x²(4x-3)-(4x-3)
Answer:
DE ≈ 16.1, ∠E ≈ 60.3°, ∠D ≈ 29.7°
Step-by-step explanation:
use pythagorean theorem:
DE² = 8² + 14² => DE = √8² + 14² ≈ 16.1
use inverse tangent function:
∠E = 
(14/8) ≈ 60.3°
∠D = (8/14) ≈ 29.7°
